if typeof myVariable isnt 'undefined' then # do stuff
Magrangs' solution will work in most cases, except when you need to distinguish between undefined and false (for example, if myVariable can be true, false or undefined).
And just to point out, you shouldn't be wrapping your conditions in parentheses, and you shouldn't be using curly braces.
The then keyword can be used if everything is on the same line, otherwise use indentation to indicate what code is inside of the condition.
if something
# this is inside the if-statement
# this is back outside of the if-statement
if (!(typeof MyVariable !== "undefined" && MyVariable !== null)) {
MyVariable = "assign a value";
}
N.b. if you make an assignment to MyVariable first, even if you set MyVariable to undefined as in this code, then this compiles to:
if (!(MyVariable != null)) {
MyVariable = "assign a value";
}
I believe this works because the != used by CoffeeScripts Existential Operator (the question mark) coerces undefined to be equal to null.
p.s. Can you actually get if (MyVariable?false){ ... } to work? It doesn't compile for me unless there's a space between the existential operator and false i.e. MyVariable? false which then makes CoffeeScript check it like a function because of the false which it thinks is a parameter for your MyVariable, for example:
if MyVariable? false
alert "Would have attempted to call MyVariable as a function"
else
alert "but didn't call MyVariable as it wasn't a function"
Produces:
if (typeof MyVariable === "function" ? MyVariable(false) : void 0) {
alert("Would have attempted to call MyVariable as a function");
} else {
alert("but didn't call MyVariable as it wasn't a function");
}
In addition to Jaider's answer above (I couldn't comment due to insufficient reputation), be careful that it's a different case if it's something inside an object/array: