Get an element by index in jQuery

I have an unordered list and the index of an li tag in that list. I have to get the li element by using that index and change its background color. Is this possible without looping the entire list? I mean, is there any method that could achieve this functionality?

Here is my code, which I believe would work...

<script type="text/javascript">
var index = 3;
</script>


<ul>
<li>India</li>
<li>Indonesia</li>
<li>China</li>
<li>United States</li>
<li>United Kingdom</li>
</ul>


<script type="text/javascript">
// I want to change bgColor of selected li element
$('ul li')[index].css({'background-color':'#343434'});


// Or, I have seen a function in jQuery doc, which gives nothing to me
$('ul li').get(index).css({'background-color':'#343434'});
</script>
164147 次浏览
小开

You can use the eq method or selector:

$('ul').find('li').eq(index).css({'background-color':'#343434'});
小开

You can use jQuery's .eq() method to get the element with a certain index.

$('ul li').eq(index).css({'background-color':'#343434'});
小开
最佳答案 
$(...)[index]      // gives you the DOM element at index
$(...).get(index)  // gives you the DOM element at index
$(...).eq(index)   // gives you the jQuery object of element at index

DOM objects don't have css function, use the last...

$('ul li').eq(index).css({'background-color':'#343434'});

docs:

.get(index) Returns: Element

.eq(index) Returns: jQuery

小开

There is another way of getting an element by index in jQuery using CSS :nth-of-type pseudo-class: 

<script>
// css selector that describes what you need:
// ul li:nth-of-type(3)
var selector = 'ul li:nth-of-type(' + index + ')';
$(selector).css({'background-color':'#343434'});
</script>

There are other selectors that you may use with jQuery to match any element that you need.

小开

You could skip the jquery and just use CSS style tagging:

 <ul>
<li>India</li>
<li>Indonesia</li>
<li style="background-color:#343434;">China</li>
<li>United States</li>
<li>United Kingdom</li>
</ul>

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