获取元素的底部和正确位置

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最佳答案

Instead of

var bottom = $(window).height() - link.height();
bottom = offset.top - bottom;

Why aren't you doing

var bottom = $(window).height() - top - link.height();

Edit: Your mistake is that you're doing

bottom = offset.top - bottom;

instead of

bottom = bottom - offset.top; // or bottom -= offset.top;

小开

You can use the .position() for this

var link = $(element);
var position = link.position(); //cache the position
var right = $(window).width() - position.left - link.width();
var bottom = $(window).height() - position.top - link.height();

小开

I think

<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>


<div>Testing</div>
<div id="result" style="margin:1em 4em; background:rgb(200,200,255); height:500px"></div>
<div style="background:rgb(200,255,200); height:3000px; width:5000px;"></div>


<script>
(function(){
var link=$("#result");


var top = link.offset().top; // position from $(document).offset().top
var bottom = top + link.height(); // position from $(document).offset().top


var left = link.offset().left; // position from $(document).offset().left
var right = left + link.width(); // position from $(document).offset().left


var bottomFromBottom = $(document).height() - bottom;
// distance from document's bottom
var rightFromRight = $(document).width() - right;
// distance from document's right


var str="";
str+="top: "+top+"<br>";
str+="bottom: "+bottom+"<br>";
str+="left: "+left+"<br>";
str+="right: "+right+"<br>";
str+="bottomFromBottom: "+bottomFromBottom+"<br>";
str+="rightFromRight: "+rightFromRight+"<br>";
link.html(str);
})();
</script>

The result are

top: 44
bottom: 544
left: 72
right: 1277
bottomFromBottom: 3068
rightFromRight: 3731

in chrome browser of mine.

When the document is scrollable, $(window).height() returns height of browser viewport, not the width of document of which some parts are hiden in scroll. See http://api.jquery.com/height/ .

小开

var link = $(element);
var offset = link.offset();


var top = offset.top;
var left = offset.left;


var bottom = top + link.outerHeight();
var right = left + link.outerWidth();

小开

// Returns bottom offset value + or - from viewport top
function offsetBottom(el, i) { i = i || 0; return $(el)[i].getBoundingClientRect().bottom }


// Returns right offset value
function offsetRight(el, i) { i = i || 0; return $(el)[i].getBoundingClientRect().right }


var bottom = offsetBottom('#logo');
var right = offsetRight('#logo');

This will find the distance from the top and left of your viewport to your element's exact edge and nothing beyond that. So say your logo was 350px and it had a left margin of 50px, variable 'right' will hold a value of 400 because that's the actual distance in pixels it took to get to the edge of your element, no matter if you have more padding or margin to the right of it.

If your box-sizing CSS property is set to border-box it will continue to work just as if it were set as the default content-box.

小开

Here is a jquery function that returns an object of any class or id on the page

var elementPosition = function(idClass) {
var element = $(idClass);
var offset = element.offset();


return {
'top': offset.top,
'right': offset.left + element.outerWidth(),
'bottom': offset.top + element.outerHeight(),
'left': offset.left,
};
};




console.log(elementPosition('#my-class-or-id'));

小开

Vanilla Javascript Answer

var c = document.getElementById("myElement").getBoundingClientRect();
var bot = c.bottom;
var rgt = c.right;

To be clear the element can be anything so long as you have allocated an id to it <img> <div> <p> etc.

for example

<img
id='myElement'
src='/img/logout.png'
className='logoutImg img-button'
alt='Logout'
/>