用 Python 读取 UTF8 CSV 文件

The .encode method gets applied to a Unicode string to make a byte-string; but you're calling it on a byte-string instead... the wrong way 'round! Look at the codecs module in the standard library and codecs.open in particular for better general solutions for reading UTF-8 encoded text files. However, for the csv module in particular, you need to pass in utf-8 data, and that's what you're already getting, so your code can be much simpler:

import csv


def unicode_csv_reader(utf8_data, dialect=csv.excel, **kwargs):
csv_reader = csv.reader(utf8_data, dialect=dialect, **kwargs)
for row in csv_reader:
yield [unicode(cell, 'utf-8') for cell in row]


filename = 'da.csv'
reader = unicode_csv_reader(open(filename))
for field1, field2, field3 in reader:
print field1, field2, field3

PS: if it turns out that your input data is NOT in utf-8, but e.g. in ISO-8859-1, then you do need a "transcoding" (if you're keen on using utf-8 at the csv module level), of the form line.decode('whateverweirdcodec').encode('utf-8') -- but probably you can just use the name of your existing encoding in the yield line in my code above, instead of 'utf-8', as csv is actually going to be just fine with ISO-8859-* encoded bytestrings.

Looking at the Latin-1 unicode table, I see the character code 00E9 "LATIN SMALL LETTER E WITH ACUTE". This is the accented character in your sample data. A simple test in Python shows that UTF-8 encoding for this character is different from the unicode (almost UTF-16) encoding.

>>> u'\u00e9'
u'\xe9'
>>> u'\u00e9'.encode('utf-8')
'\xc3\xa9'
>>>

I suggest you try to encode("UTF-8") the unicode data before calling the special unicode_csv_reader(). Simply reading the data from a file might hide the encoding, so check the actual character values.

The link to the help page is the same for python 2.6 and as far as I know there was no change in the csv module since 2.5 (besides bug fixes). Here is the code that just works without any encoding/decoding (file da.csv contains the same data as the variable data). I assume that your file should be read correctly without any conversions.

test.py:

## -*- coding: utf-8 -*-
#
# NOTE: this first line is important for the version b) read from a string(unicode) variable
#


import csv


data = \
"""0665000FS10120684,SD1200IS,Appareil photo numérique PowerShot de 10 Mpx de Canon avec trépied (SD1200IS) - Bleu
0665000FS10120689,SD1200IS,Appareil photo numérique PowerShot de 10 Mpx de Canon avec trépied (SD1200IS) - Gris
0665000FS10120687,SD1200IS,Appareil photo numérique PowerShot de 10 Mpx de Canon avec trépied (SD1200IS) - Vert"""


# a) read from a file
print 'reading from a file:'
for (f1, f2, f3) in csv.reader(open('da.csv'), dialect=csv.excel):
print (f1, f2, f3)


# b) read from a string(unicode) variable
print 'reading from a list of strings:'
reader = csv.reader(data.split('\n'), dialect=csv.excel)
for (f1, f2, f3) in reader:
print (f1, f2, f3)

da.csv:

0665000FS10120684,SD1200IS,Appareil photo numérique PowerShot de 10 Mpx de Canon avec trépied (SD1200IS) - Bleu
0665000FS10120689,SD1200IS,Appareil photo numérique PowerShot de 10 Mpx de Canon avec trépied (SD1200IS) - Gris
0665000FS10120687,SD1200IS,Appareil photo numérique PowerShot de 10 Mpx de Canon avec trépied (SD1200IS) - Vert

Using codecs.open as Alex Martelli suggested proved to be useful to me.

import codecs


delimiter = ';'
reader = codecs.open("your_filename.csv", 'r', encoding='utf-8')
for line in reader:
row = line.split(delimiter)
# do something with your row ...

Python 2.X

There is a unicode-csv library which should solve your problems, with added benefit of not naving to write any new csv-related code.

Here is a example from their readme:

>>> import unicodecsv
>>> from cStringIO import StringIO
>>> f = StringIO()
>>> w = unicodecsv.writer(f, encoding='utf-8')
>>> w.writerow((u'é', u'ñ'))
>>> f.seek(0)
>>> r = unicodecsv.reader(f, encoding='utf-8')
>>> row = r.next()
>>> print row[0], row[1]
é ñ

Python 3.X

In python 3 this is supported out of the box by the build-in csv module. See this example:

import csv
with open('some.csv', newline='', encoding='utf-8') as f:
reader = csv.reader(f)
for row in reader:
print(row)

Also checkout the answer in this post: https://stackoverflow.com/a/9347871/1338557

It suggests use of library called ucsv.py. Short and simple replacement for CSV written to address the encoding problem(utf-8) for Python 2.7. Also provides support for csv.DictReader

Edit: Adding sample code that I used:

import ucsv as csv


#Read CSV file containing the right tags to produce
fileObj = open('awol_title_strings.csv', 'rb')
dictReader = csv.DictReader(fileObj, fieldnames = ['titles', 'tags'], delimiter = ',', quotechar = '"')
#Build a dictionary from the CSV file-> {<string>:<tags to produce>}
titleStringsDict = dict()
for row in dictReader:
titleStringsDict.update({unicode(row['titles']):unicode(row['tags'])})

If you want to read a CSV File with encoding utf-8, a minimalistic approach that I recommend you is to use something like this:

with open(file_name, encoding="utf8") as csv_file:

With that statement, you can use later a CSV reader to work with.

Had the same problem on another server, but realized that locales are messed.

export LC_ALL="en_US.UTF-8"

fixed the problem

Worth noting that if nothing worked for you, you may have forgotten to escape your path.
For example, this code:

f = open("C:\Some\Path\To\file.csv")

Would result in an error:

SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 2-3: truncated \UXXXXXXXX escape

To fix, simply do:

f = open("C:\\Some\\Path\\To\\file.csv")

I suggest using the following code when you want to open the file.

open('/content/sasan.csv' , 'r', encoding='utf-8', errors='ignore' )