如何确定日期是否在 Java 中的两个日期之间?

如果所有三个日期都由 java.util.Date的实例表示,我如何检查一个日期是否在另外两个日期之间?

272957 次浏览

Like so:

Date min, max;   // assume these are set to something
Date d;          // the date in question


return d.compareTo(min) >= 0 && d.compareTo(max) <= 0;

You can use > instead of >= and < instead of <= to exclude the endpoints from the sense of "between."

This might be a bit more readable:

Date min, max;   // assume these are set to something
Date d;          // the date in question


return d.after(min) && d.before(max);

you can use getTime() and compare the returned long UTC values.

EDIT if you are sure you'll not have to deal with dates before 1970, not sure how it will behave in that case.

Another option

min.getTime() <= d.getTime() && d.getTime() <= max.getTime()

You might want to take a look at Joda Time which is a really good API for dealing with date/time. Even though if you don't really need it for the solution to your current question it is bound to save you pain in the future.

If you don't know the order of the min/max values

Date a, b;   // assume these are set to something
Date d;      // the date in question


return a.compareTo(d) * d.compareTo(b) > 0;

If you want the range to be inclusive

return a.compareTo(d) * d.compareTo(b) >= 0;

You can treat null as unconstrained with

if (a == null) {
return b == null || d.compareTo(b) < 0;
} else if (b == null) {
return a.compareTo(d) < 0;
} else {
return a.compareTo(d) * d.compareTo(b) > 0;
}
import java.util.Date;


public class IsDateBetween {


public static void main (String[] args) {


IsDateBetween idb=new IsDateBetween("12/05/2010"); // passing your Date
}
public IsDateBetween(String dd) {


long  from=Date.parse("01/01/2000");  // From some date


long to=Date.parse("12/12/2010");     // To Some Date


long check=Date.parse(dd);


int x=0;


if((check-from)>0 && (to-check)>0)
{
x=1;
}


System.out.println ("From Date is greater Than  ToDate : "+x);
}


}

Here you go:

public static void main(String[] args) throws ParseException {


SimpleDateFormat sdf = new SimpleDateFormat("MM/dd/yyyy");


String oeStartDateStr = "04/01/";
String oeEndDateStr = "11/14/";


Calendar cal = Calendar.getInstance();
Integer year = cal.get(Calendar.YEAR);


oeStartDateStr = oeStartDateStr.concat(year.toString());
oeEndDateStr = oeEndDateStr.concat(year.toString());


Date startDate = sdf.parse(oeStartDateStr);
Date endDate = sdf.parse(oeEndDateStr);
Date d = new Date();
String currDt = sdf.format(d);




if((d.after(startDate) && (d.before(endDate))) || (currDt.equals(sdf.format(startDate)) ||currDt.equals(sdf.format(endDate)))){
System.out.println("Date is between 1st april to 14th nov...");
}
else{
System.out.println("Date is not between 1st april to 14th nov...");
}
}

Here's a couple ways to do this using the Joda-Time 2.3 library.

One way is to use the simple isBefore and isAfter methods on DateTime instances. By the way, DateTime in Joda-Time is similar in concept to a java.util.Date (a moment in time on the timeline of the Universe) but includes a time zone.

Another way is to build an Interval in Joda-Time. The contains method tests if a given DateTime occurs within the span of time covered by the Interval. The beginning of the Interval is inclusive, but the endpoint is exclusive. This approach is known as "Half-Open", symbolically [).

See both ways in the following code example.

Convert the java.util.Date instances to Joda-Time DateTime instances. Simply pass the Date instance to constructor of DateTime. In practice you should also pass a specific DateTimeZone object rather than rely on JVM’s default time zone.

DateTime dateTime1 = new DateTime( new java.util.Date() ).minusWeeks( 1 );
DateTime dateTime2 = new DateTime( new java.util.Date() );
DateTime dateTime3 = new DateTime( new java.util.Date() ).plusWeeks( 1 );

Compare by testing for before/after…

boolean is1After2 = dateTime1.isAfter( dateTime2 );
boolean is2Before3 = dateTime2.isBefore( dateTime3 );


boolean is2Between1And3 = ( ( dateTime2.isAfter( dateTime1 ) ) && ( dateTime2.isBefore( dateTime3 ) ) );

Using the Interval approach instead of isAfter/isBefore…

Interval interval = new Interval( dateTime1, dateTime3 );
boolean intervalContainsDateTime2 = interval.contains( dateTime2 );

Dump to console…

System.out.println( "DateTimes: " + dateTime1 + " " + dateTime1 + " " + dateTime1 );
System.out.println( "is1After2 " + is1After2 );
System.out.println( "is2Before3 " + is2Before3 );
System.out.println( "is2Between1And3 " + is2Between1And3 );
System.out.println( "intervalContainsDateTime2 " + intervalContainsDateTime2 );

When run…

DateTimes: 2014-01-22T20:26:14.955-08:00 2014-01-22T20:26:14.955-08:00 2014-01-22T20:26:14.955-08:00
is1After2 false
is2Before3 true
is2Between1And3 true
intervalContainsDateTime2 true

Here's how to find whether today is between 2 months:

private boolean isTodayBetween(int from, int to) {
if (from < 0 || to < 0 || from > Calendar.DECEMBER || to > Calendar.DECEMBER) {
throw new IllegalArgumentException("Invalid month provided: from = " + from + " to = " + to);
}
Date now = new Date();
GregorianCalendar cal = new GregorianCalendar();
cal.setTime(now);
int thisMonth = cal.get(Calendar.MONTH);
if (from > to) {
to = to + Calendar.DECEMBER;
thisMonth = thisMonth + Calendar.DECEMBER;
}
if (thisMonth >= from && thisMonth <= to) {
return true;
}
return false;
}

and call it like:

isTodayBetween(Calendar.OCTOBER, Calendar.MARCH)

Between dates Including end points can be written as

public static boolean isDateInBetweenIncludingEndPoints(final Date min, final Date max, final Date date){
return !(date.before(min) || date.after(max));
}

NB: as @Ponmudi pointed out in the comments, this solution may not work if the dates are different at miilliseconds level.