如何以编程方式确定哪些 SQL 表具有标识列

sys.columns.is_identity = 1

e.g.,

select o.name, c.name
from sys.objects o inner join sys.columns c on o.object_id = c.object_id
where c.is_identity = 1

In SQL 2005:

select object_name(object_id), name
from sys.columns
where is_identity = 1

I think this works for SQL 2000:

SELECT
CASE WHEN C.autoval IS NOT NULL THEN
'Identity'
ELSE
'Not Identity'
AND
FROM
sysobjects O
INNER JOIN
syscolumns C
ON
O.id = C.id
WHERE
O.NAME = @TableName
AND
C.NAME = @ColumnName

This query seems to do the trick:

SELECT
sys.objects.name AS table_name,
sys.columns.name AS column_name
FROM sys.columns JOIN sys.objects
ON sys.columns.object_id=sys.objects.object_id
WHERE
sys.columns.is_identity=1
AND
sys.objects.type in (N'U')

Another way (for 2000 / 2005/2012/2014):

IF ((SELECT OBJECTPROPERTY( OBJECT_ID(N'table_name_here'), 'TableHasIdentity')) = 1)
PRINT 'Yes'
ELSE
PRINT 'No'

NOTE: table_name_here should be schema.table, unless the schema is dbo.

Another potential way to do this for SQL Server, which has less reliance on the system tables (which are subject to change, version to version) is to use the INFORMATION_SCHEMA views:

select COLUMN_NAME, TABLE_NAME
from INFORMATION_SCHEMA.COLUMNS
where COLUMNPROPERTY(object_id(TABLE_SCHEMA+'.'+TABLE_NAME), COLUMN_NAME, 'IsIdentity') = 1
order by TABLE_NAME

here's a working version for MSSQL 2000. I've modified the 2005 code found here: http://sqlfool.com/2011/01/identity-columns-are-you-nearing-the-limits/

/* Define how close we are to the value limit
before we start throwing up the red flag.
The higher the value, the closer to the limit. */
DECLARE @threshold DECIMAL(3,2);
SET @threshold = .85;


/* Create a temp table */
CREATE TABLE #identityStatus
(
database_name     VARCHAR(128)
, table_name        VARCHAR(128)
, column_name       VARCHAR(128)
, data_type         VARCHAR(128)
, last_value        BIGINT
, max_value         BIGINT
);


DECLARE @dbname sysname;
DECLARE @sql nvarchar(4000);


-- Use an cursor to iterate through the databases since in 2000 there's no sp_MSForEachDB command...


DECLARE c cursor FAST_FORWARD FOR
SELECT
name
FROM
master.dbo.sysdatabases
WHERE
name NOT IN('master', 'model', 'msdb', 'tempdb');


OPEN c;


FETCH NEXT FROM c INTO @dbname;


WHILE @@FETCH_STATUS = 0
BEGIN
SET @sql = N'Use [' + @dbname + '];
Insert Into #identityStatus
Select ''' + @dbname + ''' As [database_name]
, Object_Name(id.id) As [table_name]
, id.name As [column_name]
, t.name As [data_type]
, IDENT_CURRENT(Object_Name(id.id)) As [last_value]
, Case
When t.name = ''tinyint''   Then 255
When t.name = ''smallint''  Then 32767
When t.name = ''int''       Then 2147483647
When t.name = ''bigint''    Then 9223372036854775807
End As [max_value]
From
syscolumns As id
Join systypes As t On id.xtype = t.xtype
Where
id.colstat&1 = 1    -- this identifies the identity columns (as far as I know)
';


EXECUTE sp_executesql @sql;


FETCH NEXT FROM c INTO @dbname;
END


CLOSE c;
DEALLOCATE c;


/* Retrieve our results and format it all prettily */
SELECT database_name
, table_name
, column_name
, data_type
, last_value
, CASE
WHEN last_value < 0 THEN 100
ELSE (1 - CAST(last_value AS FLOAT(4)) / max_value) * 100
END AS [percentLeft]
, CASE
WHEN CAST(last_value AS FLOAT(4)) / max_value >= @threshold
THEN 'warning: approaching max limit'
ELSE 'okay'
END AS [id_status]
FROM #identityStatus
ORDER BY percentLeft;


/* Clean up after ourselves */
DROP TABLE #identityStatus;

This worked for me using Sql Server 2008:

USE <database_name>;
GO
SELECT SCHEMA_NAME(schema_id) AS schema_name
, t.name AS table_name
, c.name AS column_name
FROM sys.tables AS t
JOIN sys.identity_columns c ON t.object_id = c.object_id
ORDER BY schema_name, table_name;
GO

Use this :

DECLARE @Table_Name VARCHAR(100)
DECLARE @Column_Name VARCHAR(100)
SET @Table_Name = ''
SET @Column_Name = ''


SELECT  RowNumber = ROW_NUMBER() OVER ( PARTITION BY T.[Name] ORDER BY T.[Name], C.column_id ) ,
SCHEMA_NAME(T.schema_id) AS SchemaName ,
T.[Name] AS Table_Name ,
C.[Name] AS Field_Name ,
sysType.name ,
C.max_length ,
C.is_nullable ,
C.is_identity ,
C.scale ,
C.precision
FROM    Sys.Tables AS T
LEFT JOIN Sys.Columns AS C ON ( T.[Object_Id] = C.[Object_Id] )
LEFT JOIN sys.types AS sysType ON ( C.user_type_id = sysType.user_type_id )
WHERE   ( Type = 'U' )
AND ( C.Name LIKE '%' + @Column_Name + '%' )
AND ( T.Name LIKE '%' + @Table_Name + '%' )
ORDER BY T.[Name] ,
C.column_id

List of tables without Identity column based on Guillermo answer:

SELECT DISTINCT TABLE_NAME
FROM            INFORMATION_SCHEMA.COLUMNS
WHERE        (TABLE_SCHEMA = 'dbo') AND (OBJECTPROPERTY(OBJECT_ID(TABLE_NAME), 'TableHasIdentity') = 0)
ORDER BY TABLE_NAME

这适用于SQL Server 2005、2008和2012。 I found that the sys.identity_columns did not contain all my tables with identity columns.

SELECT a.name AS TableName, b.name AS IdentityColumn
FROM sys.sysobjects a
JOIN sys.syscolumns b
ON a.id = b.id
WHERE is_identity = 1
ORDER BY name;

Looking at the documentation page the status column can also be utilized. Also you can add the four part identifier and it will work across different servers.

SELECT a.name AS TableName, b.name AS IdentityColumn
FROM [YOUR_SERVER_NAME].[YOUR_DB_NAME].sys.sysobjects a
JOIN [YOUR_SERVER_NAME].[YOUR_DB_NAME].sys.syscolumns b
ON a.id = b.id
WHERE is_identity = 1
ORDER BY name;

Source: https://msdn.microsoft.com/en-us/library/ms186816.aspx

The following query work for me:

select  TABLE_NAME tabla,COLUMN_NAME columna
from    INFORMATION_SCHEMA.COLUMNS
where   COLUMNPROPERTY(object_id(TABLE_SCHEMA+'.'+TABLE_NAME), COLUMN_NAME, 'IsIdentity') = 1
order by TABLE_NAME

By some reason sql server save some identity columns in different tables, the code that work for me, is the following:

select      TABLE_NAME tabla,COLUMN_NAME columna
from        INFORMATION_SCHEMA.COLUMNS
where       COLUMNPROPERTY(object_id(TABLE_SCHEMA+'.'+TABLE_NAME), COLUMN_NAME, 'IsIdentity') = 1
union all
select      o.name tabla, c.name columna
from        sys.objects o
inner join  sys.columns c on o.object_id = c.object_id
where       c.is_identity = 1

Get all columns with Identity. Modern version for MSSQL 2017+. Locks down to specific database:

SELECT
[COLUMN_NAME]
, [TABLE_NAME]
, [TABLE_CATALOG]
FROM
[INFORMATION_SCHEMA].[COLUMNS]
WHERE
COLUMNPROPERTY(OBJECT_ID(CONCAT_WS('.' ,[TABLE_CATALOG] ,[TABLE_SCHEMA] ,[TABLE_NAME])) ,[COLUMN_NAME] ,'IsIdentity') = 1
ORDER BY
[TABLE_NAME]