I would recommend reading a book on C++ before you go any further, as it would be helpful to get a firmer footing. Accelerated C++ by Koenig and Moo is excellent.
GetCurrentDirectory() gets the current directory which is where the exe is invoked from. To get the location of the exe, use GetModuleFileName(NULL ...). if you have the handle to the exe, or you can derive it from GetCommandLine() if you don't.
As Mr. Butterworth points out, you don't need a handle.
Please don't forget to initialize your buffers to something before utilizing them. And just as important, give your string buffers space for the ending null
TCHAR path[MAX_PATH+1] = L"";
DWORD len = GetCurrentDirectory(MAX_PATH, path);
#include <windows.h>
using namespace std;
// The directory path returned by native GetCurrentDirectory() no end backslash
string getCurrentDirectoryOnWindows()
{
const unsigned long maxDir = 260;
char currentDir[maxDir];
GetCurrentDirectory(maxDir, currentDir);
return string(currentDir);
}
The question is not clear whether the current working directory is wanted or the path of the directory containing the executable.
Most answers seem to answer the latter.
But for the former, and for the second part of the question of creating the file, the C++17 standard now incorporates the filesystem library which simplifies this a lot:
This fetches the current working directory, adds the filename to the path and creates an empty file. Note that the path object takes care of os dependent path handling, so cwd.string() returns an os dependent path string. Neato.
argv[] is pretty much an array containing arguments you ran the .exe with, but the first one is always a path to the executable. If I build this the console shows:
C:\Users\Ulisse\source\repos\altcmd\Debug\currentdir.exe