Java 中的整数到两位十六进制

我需要在 Java 中将一个整数值改为2位十六进制值。 谢谢

我最大的数字是63，最小的是0。 我想要一个小值的前导零。

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Integer.toHexString(42);

Javadoc: http://docs.oracle.com/javase/6/docs/api/java/lang/Integer.html#toHexString(int)

Note that this may give you more than 2 digits, however! (An Integer is 4 bytes, so you could potentially get back 8 characters.)

Here's a bit of a hack to get your padding, as long as you are absolutely sure that you're only dealing with single-byte values (255 or less):

Integer.toHexString(0x100 | 42).substring(1)

Many more (and better) solutions at Left padding integers (non-decimal format) with zeros in Java.

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Use Integer.toHexString(). Dont forget to pad with a leading zero if you only end up with one digit. If your integer is greater than 255 you'll get more than 2 digits.

StringBuilder sb = new StringBuilder();
sb.append(Integer.toHexString(myInt));
if (sb.length() < 2) {
sb.insert(0, '0'); // pad with leading zero if needed
}
String hex = sb.toString();
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If you just need to print them try this: 

for(int a = 0; a < 255; a++){
if( a % 16 == 0){
System.out.println();
}
System.out.printf("%02x ", a);
}
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String.format("%02X", (0xFF & value));
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最佳答案 
String.format("%02X", value);

If you use X instead of x as suggested by aristar, then you don't need to use .toUpperCase().

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i use this to get a string representing the equivalent hex value of an integer separated by space for every byte EX : hex val of 260 in 4 bytes = 00 00 01 04

    public static String getHexValString(Integer val, int bytePercision){
StringBuilder sb = new StringBuilder();
sb.append(Integer.toHexString(val));


while(sb.length() < bytePercision*2){
sb.insert(0,'0');// pad with leading zero
}


int l = sb.length(); // total string length before spaces
int r = l/2; //num of rquired iterations


for (int i=1; i < r;  i++){
int x = l-(2*i); //space postion
sb.insert(x, ' ');
}
return sb.toString().toUpperCase();
}


public static void main(String []args){
System.out.println("hex val of 260 in 4 bytes = " + getHexValString(260,4));
}
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According to GabrielOshiro, If you want format integer to length 8, try this

String.format("0x%08X", 20) //print 0x00000014

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