如何在 C 中将字符转换为整数？

可能的复制品:
如何将一个字符转换为整型
 字符到整数

有人能告诉我如何将 char转换成 int吗？

char c[]={'1',':','3'};


int i=int(c[0]);


printf("%d",i);

当我尝试这个，它给49。

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小开

The standard function atoi() will likely do what you want.

A simple example using "atoi":

#include <stdlib.h>
#include <unistd.h>


int main(int argc, char *argv[])
{
int useconds = atoi(argv[1]);
usleep(useconds);
}

小开

In the old days, when we could assume that most computers used ASCII, we would just do

int i = c[0] - '0';

~~But in these days of Unicode, it's not a good idea. It was never a good idea if your code had to run on a non-ASCII computer.~~

Edit: Although it looks hackish, evidently it is guaranteed by the standard to work. Thanks @Earwicker.