MySQL‘ Order By’-正确排序字母数字

This type of question has been asked previously.

The type of sorting you are talking about is called "Natural Sorting". The data on which you want to do sort is alphanumeric. It would be better to create a new column for sorting.

For further help check natural-sort-in-mysql

I hate this, but this will work

order by lpad(name, 10, 0)  <-- assuming maximum string length is 10
<-- you can adjust to a bigger length if you want to

People use different tricks to do this. I Googled and find out some results each follow different tricks. Have a look at them:

• Alpha Numeric Sorting in MySQL
• Natural Sorting in MySQL
• Sorting of numeric values mixed with alphanumeric values
• mySQL natural sort
• Natural Sort in MySQL

Edit:

I have just added the code of each link for future visitors.

Alpha Numeric Sorting in MySQL

Given input

1A 1a 10A 9B 21C 1C 1D

Expected output

1A 1C 1D 1a 9B 10A 21C

Query

Bin Way
===================================
SELECT
tbl_column,
BIN(tbl_column) AS binray_not_needed_column
FROM db_table
ORDER BY binray_not_needed_column ASC , tbl_column ASC


-----------------------


Cast Way
===================================
SELECT
tbl_column,
CAST(tbl_column as SIGNED) AS casted_column
FROM db_table
ORDER BY casted_column ASC , tbl_column ASC

Natural Sorting in MySQL

Given input

Table: sorting_test
-------------------------- -------------
| alphanumeric VARCHAR(75) | integer INT |
-------------------------- -------------
| test1                    | 1           |
| test12                   | 2           |
| test13                   | 3           |
| test2                    | 4           |
| test3                    | 5           |
-------------------------- -------------

Expected Output

 -------------------------- -------------
| alphanumeric VARCHAR(75) | integer INT |
-------------------------- -------------
| test1                    | 1           |
| test2                    | 4           |
| test3                    | 5           |
| test12                   | 2           |
| test13                   | 3           |
-------------------------- -------------

Query

SELECT alphanumeric, integer
FROM sorting_test
ORDER BY LENGTH(alphanumeric), alphanumeric

Sorting of numeric values mixed with alphanumeric values

Given input

2a, 12, 5b, 5a, 10, 11, 1, 4b

Expected Output

1, 2a, 4b, 5a, 5b, 10, 11, 12

Query

SELECT version
FROM version_sorting
ORDER BY CAST(version AS UNSIGNED), version;

Hope this helps

I know this post is closed but I think my way could help some people. So there it is :

My dataset is very similar but is a bit more complex. It has numbers, alphanumeric data :

1
2
Chair
3
0
4
5
-
Table
10
13
19
Windows
99
102
Dog

I would like to have the '-' symbol at first, then the numbers, then the text.

So I go like this :

SELECT name, (name = '-') boolDash, (name = '0') boolZero, (name+0 > 0) boolNum
FROM table
ORDER BY boolDash DESC, boolZero DESC, boolNum DESC, (name+0), name

The result should be something :

-
0
1
2
3
4
5
10
13
99
102
Chair
Dog
Table
Windows

The whole idea is doing some simple check into the SELECT and sorting with the result.

Just do this:

SELECT * FROM table ORDER BY column `name`+0 ASC

Appending the +0 will mean that:

0, 10, 11, 2, 3, 4

becomes :

0, 2, 3, 4, 10, 11

I had some good results with

SELECT alphanumeric, integer FROM sorting_test ORDER BY CAST(alphanumeric AS UNSIGNED), alphanumeric ASC

This should sort alphanumeric field like: 1/ Number only, order by 1,2,3,4,5,6,7,8,9,10,11 etc... 2/ Then field with text like: 1foo, 2bar, aaa11aa, aaa22aa, b5452 etc...

SELECT  MyField
FROM MyTable
order by
IF( MyField REGEXP '^-?[0-9]+$' = 0,
9999999999 ,
CAST(MyField AS DECIMAL)
), MyField

The query check if the data is a number, if not put it to 9999999999 , then order first on this column, then order on data with text

Good luck!

SELECT
s.id, s.name,  LENGTH(s.name) len, ASCII(s.name) ASCCCI
FROM table_name s
ORDER BY ASCCCI,len,NAME ASC;

Instead of trying to write some function and slow down the SELECT query, I thought of another way of doing this...

Create an extra field in your database that holds the result from the following Class and when you insert a new row, run the field value that will be naturally sorted through this class and save its result in the extra field. Then instead of sorting by your original field, sort by the extra field.

String nsFieldVal = new NaturalSortString(getFieldValue(), 4).toString()

The above means:
- Create a NaturalSortString for the String returned from getFieldValue()
- Allow up to 4 bytes to store each character or number (4 bytes = ffff = 65535)


| field(32)  |  nsfield(161)                            |
a1            300610001

String sortString = new NaturalSortString(getString(), 4).toString()

import StringUtils;


/**
* Creates a string that allows natural sorting in a SQL database
* eg, 0 1 1a 2 3 3a 10 100 a a1 a1a1 b
*/
public class NaturalSortString {


private String inStr;
private int byteSize;
private StringBuilder out = new StringBuilder();


/**
* A byte stores the hex value (0 to f) of a letter or number.
* Since a letter is two bytes, the minimum byteSize is 2.
*
* 2 bytes = 00 - ff  (max number is 255)
* 3 bytes = 000 - fff (max number is 4095)
* 4 bytes = 0000 - ffff (max number is 65535)
*
* For example:
* dog123 = 64,6F,67,7B and thus byteSize >= 2.
* dog280 = 64,6F,67,118 and thus byteSize >= 3.
*
* For example:
* The String, "There are 1000000 spots on a dalmatian" would require a byteSize that can
* store the number '1000000' which in hex is 'f4240' and thus the byteSize must be at least 5
*
* The dbColumn size to store the NaturalSortString is calculated as:
* > originalStringColumnSize x byteSize + 1
* The extra '1' is a marker for String type - Letter, Number, Symbol
* Thus, if the originalStringColumn is varchar(32) and the byteSize is 5:
* > NaturalSortStringColumnSize = 32 x 5 + 1 = varchar(161)
*
* The byteSize must be the same for all NaturalSortStrings created in the same table.
* If you need to change the byteSize (for instance, to accommodate larger numbers), you will
* need to recalculate the NaturalSortString for each existing row using the new byteSize.
*
* @param str        String to create a natural sort string from
* @param byteSize   Per character storage byte size (minimum 2)
* @throws Exception See the error description thrown
*/
public NaturalSortString(String str, int byteSize) throws Exception {
if (str == null || str.isEmpty()) return;
this.inStr = str;
this.byteSize = Math.max(2, byteSize);  // minimum of 2 bytes to hold a character
setStringType();
iterateString();
}


private void setStringType() {
char firstchar = inStr.toLowerCase().subSequence(0, 1).charAt(0);
if (Character.isLetter(firstchar))     // letters third
out.append(3);
else if (Character.isDigit(firstchar)) // numbers second
out.append(2);
else                                   // non-alphanumeric first
out.append(1);
}


private void iterateString() throws Exception {
StringBuilder n = new StringBuilder();
for (char c : inStr.toLowerCase().toCharArray()) { // lowercase for CASE INSENSITIVE sorting
if (Character.isDigit(c)) {
// group numbers
n.append(c);
continue;
}
if (n.length() > 0) {
addInteger(n.toString());
n = new StringBuilder();
}
addCharacter(c);
}
if (n.length() > 0) {
addInteger(n.toString());
}
}


private void addInteger(String s) throws Exception {
int i = Integer.parseInt(s);
if (i >= (Math.pow(16, byteSize)))
throw new Exception("naturalsort_bytesize_exceeded");
out.append(StringUtils.padLeft(Integer.toHexString(i), byteSize));
}


private void addCharacter(char c) {
//TODO: Add rest of accented characters
if (c >= 224 && c <= 229) // set accented a to a
c = 'a';
else if (c >= 232 && c <= 235) // set accented e to e
c = 'e';
else if (c >= 236 && c <= 239) // set accented i to i
c = 'i';
else if (c >= 242 && c <= 246) // set accented o to o
c = 'o';
else if (c >= 249 && c <= 252) // set accented u to u
c = 'u';
else if (c >= 253 && c <= 255) // set accented y to y
c = 'y';


out.append(StringUtils.padLeft(Integer.toHexString(c), byteSize));
}


@Override
public String toString() {
return out.toString();
}
}

For completeness, below is the StringUtils.padLeft method:

public static String padLeft(String s, int n) {
if (n - s.length() == 0) return s;
return String.format("%0" + (n - s.length()) + "d%s", 0, s);
}

The result should come out like the following

-1
-a
0
1
1.0
1.01
1.1.1
1a
1b
9
10
10a
10ab
11
12
12abcd
100
a
a1a1
a1a2
a-1
a-2
áviacion
b
c1
c2
c12
c100
d
d1.1.1
e

If you need to sort an alpha-numeric column that does not have any standard format whatsoever

SELECT * FROM table ORDER BY (name = '0') DESC, (name+0 > 0) DESC, name+0 ASC, name ASC

You can adapt this solution to include support for non-alphanumeric characters if desired using additional logic.

This works for type of data: Data1, Data2, Data3 ......,Data21. Means "Data" String is common in all rows.

For ORDER BY ASC it will sort perfectly, For ORDER BY DESC not suitable.

SELECT * FROM table_name ORDER BY LENGTH(column_name), column_name ASC;

Try this For ORDER BY DESC

SELECT * FROM testdata ORDER BY LENGHT(name) DESC, name DESC

SELECT length(actual_project_name),actual_project_name,
SUBSTRING_INDEX(actual_project_name,'-',1) as aaaaaa,
SUBSTRING_INDEX(actual_project_name, '-', -1) as actual_project_number,
concat(SUBSTRING_INDEX(actual_project_name,'-',1),SUBSTRING_INDEX(actual_project_name, '-', -1)) as a
FROM ctts.test22
order by
SUBSTRING_INDEX(actual_project_name,'-',1) asc,cast(SUBSTRING_INDEX(actual_project_name, '-', -1) as unsigned) asc

MySQL ORDER BY Sorting alphanumeric on correct order

example:

SELECT `alphanumericCol` FROM `tableName` ORDER BY
SUBSTR(`alphanumericCol` FROM 1 FOR 1),
LPAD(lower(`alphanumericCol`), 10,0) ASC

output:

1
2
11
21
100
101
102
104
S-104A
S-105
S-107
S-111

This is a simple example.

SELECT HEX(some_col) h
FROM some_table
ORDER BY h

This is from tutorials point

SELECT * FROM yourTableName ORDER BY
SUBSTR(yourColumnName FROM 1 FOR 2),
CAST(SUBSTR(yourColumnName FROM 2) AS UNSIGNED);

it is slightly different from another answer of this thread

For reference, this is the original link https://www.tutorialspoint.com/mysql-order-by-string-with-numbers

Another point regarding UNSIGNED is written here https://electrictoolbox.com/mysql-order-string-as-int/

While this has REGEX too https://www.sitepoint.com/community/t/how-to-sort-text-with-numbers-with-sql/346088/9

Assuming varchar field containing number, decimal, alphanumeric and string, for example :

Let's suppose Column Name is "RandomValues" and Table name is "SortingTest"


A1
120
2.23
3
0
2
Apple
Zebra
Banana
23
86.Akjf9
Abtuo332
66.9
22
ABC

SELECT * FROM SortingTest order by IF( RandomValues REGEXP '^-?[0-9,.]+$' = 0, 9999999999 , CAST(RandomValues AS DECIMAL) ), RandomValues

Above query will do sorting on number & decimal values first and after that all alphanumeric values got sorted.

This will always put the values starting with a number first:

ORDER BY my_column REGEXP '^[0-9]' DESC, length(my_column  + 0), my_column ";

Works as follows:

• Step1 - Is first char a digit? 1 if true, 0 if false, so order by this DESC
• Step2 - How many digits is the number? Order by this ASC
• Step3 - Order by the field itself

Input:

  ('100'),
('1'),
('10'),
('0'),
('2'),
('2a'),
('12sdfa'),
('12 sdfa'),
('Bar nah');

Output:

0
1
2
2a
10
12 sdfa
12sdfa
100
Bar nah

Really problematic for my scenario...

select * from table order by lpad(column, 20, 0)

My column is a varchar, but has numeric input (1, 2, 3...) , mixed numeric (1A, 1B, 1C) and too string data (INT, SHIP)

order by len(xxxxx),xxxxx

Eg:

SELECT * from customer order by len(xxxxx),xxxxx