To show only file name without the entire directory path

ls /home/user/new/*.txt prints all txt files in that directory. However it prints the output as follows:

[me@comp]$ ls /home/user/new/*.txt
/home/user/new/file1.txt    /home/user/new/file2.txt    /home/user/new/file3.txt

and so on.

I want to run the ls command not from the /home/user/new/ directory thus I have to give the full directory name, yet I want the output to be only as

[me@comp]$ ls /home/user/new/*.txt
file1.txt    file2.txt    file3.txt

I don't want the entire path. Only filename is needed. This issues has to be solved using ls command, as its output is meant for another program.

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最佳答案

ls whateveryouwant | xargs -n 1 basename

Does that work for you?

Otherwise you can (cd /the/directory && ls) (yes, parentheses intended)

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There are several ways you can achieve this. One would be something like:

for filepath in /path/to/dir/*
do
filename=$(basename $filepath)


... whatever you want to do with the file here
done
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you could add an sed script to your commandline:

ls /home/user/new/*.txt | sed -r 's/^.+\///'
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I prefer the base name which is already answered by fge. Another way is :

ls /home/user/new/*.txt|awk -F"/" '{print $NF}'

one more ugly way is :

ls /home/user/new/*.txt| perl -pe 's/\//\n/g'|tail -1
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A fancy way to solve it is by using twice "rev" and "cut":

find ./ -name "*.txt" | rev | cut -d '/' -f1 | rev
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No need for Xargs and all , ls is more than enough.

ls -1 *.txt

displays row wise

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just hoping to be helpful to someone as old problems seem to come back every now and again and I always find good tips here.

My problem was to list in a text file all the names of the "*.txt" files in a certain directory without path and without extension from a Datastage 7.5 sequence.

The solution we used is:

ls /home/user/new/*.txt | xargs -n 1 basename | cut -d '.' -f1 > name_list.txt
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(cd dir && ls)

will only output filenames in dir. Use ls -1 if you want one per line.

(Changed ; to && as per Sactiw's comment).

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There are lots of way we can do that and simply you can try following.

ls /home/user/new | tr '\n' '\n' | grep .txt

Another method:

cd /home/user/new && ls *.txt
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The selected answer did not work for me, as I had spaces, quotes and other strange characters in my filenames. To quote the input for basename, you should use:

ls /path/to/my/directory | xargs -n1 -I{} basename "{}"

This is guaranteed to work, regardless of what the files are called.

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Use the basename command:

basename /home/user/new/*.txt
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When you want to list names in a path but they have different file extensions.

me@server:/var/backups$ ls -1 *.zip && ls -1 *.gz

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Here is another way:

ls -1 /home/user/new/*.txt|rev|cut -d'/' -f1|rev
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You could also pipe to grep and pull everything after the last forward slash. It looks goofy, but I think a defensive grep should be fine unless (like some kind of maniac) you have forward slashes within your filenames.

ls folderpathwithcriteria | grep -P -o -e "[^/]*$"


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