Get the Year/Month/Day from a datetime in php?

I used date('w', timestamp) and date('w', timestamp) to know the day, date('n', timestamp) for months, etc.

Now I'm using datetime and I'd like to know what are the equivalent functions to get a day, a month, etc from a datetime.

PS: I know I could use UNIX_TIMESTAMP() in a SQL query but I prefer avoiding timestamps using in my code.

200064 次浏览
小开
最佳答案

Use DateTime with DateTime::format()

$datetime = new DateTime($dateTimeString);
echo $datetime->format('w');
小开

Check out the manual: http://www.php.net/manual/en/datetime.format.php

<?php
$date = new DateTime('2000-01-01');
echo $date->format('Y-m-d H:i:s');
?>

Will output: 2000-01-01 00:00:00

小开

Try below code if you want to use php loop to display

<span>
<select name="birth_month">
<?php for( $m=1; $m<=12; ++$m ) {
$month_label = date('F', mktime(0, 0, 0, $m, 1));
?>
<option value="<?php echo $month_label; ?>"><?php echo $month_label; ?></option>
<?php } ?>
</select>
</span>
<span>
<select name="birth_day">
<?php
$start_date = 1;
$end_date   = 31;
for( $j=$start_date; $j<=$end_date; $j++ ) {
echo '<option value='.$j.'>'.$j.'</option>';
}
?>
</select>
</span>
<span>
<select name="birth_year">
<?php
$year = date('Y');
$min = $year - 60;
$max = $year;
for( $i=$max; $i>=$min; $i-- ) {
echo '<option value='.$i.'>'.$i.'</option>';
}
?>
</select>
</span>

提交答案