Python 中的简单“ if”或逻辑语句

如何用 Python 编写下面的代码？

if key < 1 or key > 34:

我已经尝试了所有我能想到的方法，但是我发现这非常令人沮丧。

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最佳答案

If key isn't an int or float but a string, you need to convert it to an int first by doing

key = int(key)

or to a float by doing

key = float(key)

Otherwise, what you have in your question should work, but

if (key < 1) or (key > 34):

if not (1 <= key <= 34):

would be a bit clearer.

小开

Here's a Boolean thing:

if (not suffix == "flac" )  or (not suffix == "cue" ):   # WRONG! FAILS
print  filename + ' is not a flac or cue file'

but

if not (suffix == "flac"  or suffix == "cue" ):     # CORRECT!
print  filename + ' is not a flac or cue file'

(not a) or (not b) == not ( a and b ) , is false only if a and b are both true

not (a or b) is true only if a and be are both false.