删除 String 中的多个空格和新行

假设我们有这样的字符串:

Hello, my\n       name is Michael.

我怎样才能删除这个新的行，并剥离这些空格后，成为一个字符串的内部得到这个？

Hello, my name is Michael.

ruby
string

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The simplest way would probably be

s = "Hello, my\n       name is Michael."
s.split.join(' ') #=> "Hello, my name is Michael."

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Use String#gsub:

s = "Hello, my\n       name is Michael."
s.gsub(/\s+/, " ")

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this regex will replace instance of 1 or more white spaces with 1 white space, p.s \s will replace all white space characters which includes \s\t\r\n\f:

a_string.gsub!(/\s+/, ' ')

Similarly for only carriage return

str.gsub!(/\n/, " ")

First replace all \n with white space, then use the remove multiple white space regex.

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my_string = "Hello, my\n       name is Michael."
my_string = my_string.gsub( /\s+/, " " )

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最佳答案

check out Rails squish method:

http://apidock.com/rails/String/squish

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To illustrate Rubys built in squeeze:

string.gsub("\n", ' ').squeeze(' ')

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Try This:

s = "Hello, my\n       name is Michael."
s.gsub(/\n\s+/, " ")

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Use squish
currency = " XCD"
str = currency.squish
str = "XCD" #=> "XCD"

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You can add just the squish method (and nothing else) to Ruby by including just this Ruby Facet:

https://github.com/rubyworks/facets/blob/master/lib/core/facets/string/squish.rb

require 'facets/string/squish'

Then use

"my    \n   string".squish #=> "my string"

Doesn't require Rails.