如何在Python中将datetime对象转换为自epoch (unix时间)的毫秒?

>>> import datetime
>>> # replace datetime.datetime.now() with your datetime object
>>> int(datetime.datetime.now().strftime("%s")) * 1000
1312908481000

或者时间模块的帮助(没有日期格式):

>>> import datetime, time
>>> # replace datetime.datetime.now() with your datetime object
>>> time.mktime(datetime.datetime.now().timetuple()) * 1000
1312908681000.0

已回答的帮助来自:http://pleac.sourceforge.net/pleac_python/datesandtimes.html

文档:

• time.mktime
• datetime.timetuple

import time
seconds_since_epoch = time.mktime(your_datetime.timetuple()) * 1000

在我看来，最简单的方法是

import datetime


epoch = datetime.datetime.utcfromtimestamp(0)


def unix_time_millis(dt):
return (dt - epoch).total_seconds() * 1000.0

我是这样做的:

from datetime import datetime
from time import mktime


dt = datetime.now()
sec_since_epoch = mktime(dt.timetuple()) + dt.microsecond/1000000.0


millis_since_epoch = sec_since_epoch * 1000

>>> import datetime
>>> import time
>>> import calendar


>>> #your datetime object
>>> now = datetime.datetime.now()
>>> now
datetime.datetime(2013, 3, 19, 13, 0, 9, 351812)


>>> #use datetime module's timetuple method to get a `time.struct_time` object.[1]
>>> tt = datetime.datetime.timetuple(now)
>>> tt
time.struct_time(tm_year=2013, tm_mon=3, tm_mday=19, tm_hour=13, tm_min=0, tm_sec=9,     tm_wday=1, tm_yday=78, tm_isdst=-1)


>>> #If your datetime object is in utc you do this way. [2](see the first table on docs)
>>> sec_epoch_utc = calendar.timegm(tt) * 1000
>>> sec_epoch_utc
1363698009


>>> #If your datetime object is in local timeformat you do this way
>>> sec_epoch_loc = time.mktime(tt) * 1000
>>> sec_epoch_loc
1363678209.0

[1] http://docs.python.org/2/library/datetime.html#datetime.date.timetuple

[2] http://docs.python.org/2/library/time.html

你可以用德罗宁去时空旅行!

import datetime
import delorean
dt = datetime.datetime.utcnow()
delorean.Delorean(dt, timezone="UTC").epoch

http://delorean.readthedocs.org/en/latest/quickstart.html , < / p >

from datetime import datetime
from calendar import timegm


# Note: if you pass in a naive dttm object it's assumed to already be in UTC
def unix_time(dttm=None):
if dttm is None:
dttm = datetime.utcnow()


return timegm(dttm.utctimetuple())


print "Unix time now: %d" % unix_time()
print "Unix timestamp from an existing dttm: %d" % unix_time(datetime(2014, 12, 30, 12, 0))

在Python 3.3中，添加了新方法timestamp:

import datetime
seconds_since_epoch = datetime.datetime.now().timestamp()

你的问题说你需要毫秒，你可以得到这样的毫秒:

milliseconds_since_epoch = datetime.datetime.now().timestamp() * 1000

如果在naive datetime对象上使用timestamp，则它假定该对象位于本地时区。如果您不希望发生这种情况，请使用时区感知的datetime对象。

这是另一种形式的解决方案与规范化的时间对象:

def to_unix_time(timestamp):
epoch = datetime.datetime.utcfromtimestamp(0) # start of epoch time
my_time = datetime.datetime.strptime(timestamp, "%Y/%m/%d %H:%M:%S.%f") # plugin your time object
delta = my_time - epoch
return delta.total_seconds() * 1000.0

time模块的Python 2.7文档 .的建议

这是将datetime转换为unixtimestampmillis的另一个解决方案。

private static readonly DateTime UnixEpoch = new DateTime(1970, 1, 1, 0, 0, 0, DateTimeKind.Utc);


public static long GetCurrentUnixTimestampMillis()
{
DateTime localDateTime, univDateTime;
localDateTime = DateTime.Now;
univDateTime = localDateTime.ToUniversalTime();
return (long)(univDateTime - UnixEpoch).TotalMilliseconds;
}

一段熊猫代码:

import pandas


def to_millis(dt):
return int(pandas.to_datetime(dt).value / 1000000)

下面是一个基于上面答案的函数

def getDateToEpoch(myDateTime):
res = (datetime.datetime(myDateTime.year,myDateTime.month,myDateTime.day,myDateTime.hour,myDateTime.minute,myDateTime.second) - datetime.datetime(1970,1,1)).total_seconds()
return res

很多答案在python2中不起作用，或者没有从datetime中保存毫秒。这对我很有用

def datetime_to_ms_epoch(dt):
microseconds = time.mktime(dt.timetuple()) * 1000000 + dt.microsecond
return int(round(microseconds / float(1000)))