There is not really a try/catch in bash (i assume you're using bash), but you can achieve a quite similar behaviour using && or ||.
In this example, you want to run fallback_command if a_commandfails (returns a non-zero value):
a_command || fallback_command
And in this example, you want to execute second_command if a_commandis successful (returns 0):
a_command && second_command
They can easily be mixed together by using a subshell, for example, the following command will execute a_command, if it succeeds it will then run other_command, but if a_command or other_command fails, fallback_command will be executed:
The if/else structure and exit codes can help you fake some of it. This should work in Bash or Bourne (sh).
if foo ; then
else
e=$? # return code from if
if [ "${e}" -eq "1"]; then
echo "Foo returned exit code 1"
elif [ "${e}" -gt "1"]; then
echo "Foo returned BAD exit code ${e}"
fi
fi
Exceptionhandling using try/catch blocks is not supported in bash, however, you might wanna try looking at the BANGSH framework which supports it (its a bit like jquery for bash).
However, exceptionhandling without cascading try/catch-blocks is similar to eventhandling, which is possible in almost any language with array-support.
If you want to keep your code nice and tidy (without if/else verbosity), I would recommend to use events.
The suggestion which MatToufoutu recommends (using || and &&) is not recommended for functions, but ok for simple commands. (see BashPitfalls about the risks)
Use following to handle error properly where error_exit is function that accepts one argument. In case if argument is not passed then it will throw unknown error with LineNo where actually error is happening. Please experiment before actually uses for production -
#!/bin/bash
PROGNAME=$(basename $0)
error_exit()
{
echo "${PROGNAME}: ${1:-"Unknown Error"}" 1>&2
exit 1
}
echo "Example of error with line number and message"
error_exit "$LINENO: An error has occurred."