正则表达式检测多个字符串之一

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最佳答案

Use the pipe symbol to indicate "or":

/a@(foo|bar|baz)\b/

If you don't want the capture-group, use the non-capturing grouping symbol:

/a@(?:foo|bar|baz)\b/

(Of course I'm assuming "a" is OK for the front of the email address! You should replace that with a suitable regex.)

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should be more generic, the a shouldn't count, although the @ should.

/@(foo|bar|baz)(?:\W|$)/

Here is a good reference on regex.

edit: change ending to allow end of pattern or word break. now assuming foo/bar/baz are full domain names.

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^(a|b)@(foo|bar|baz)$

if you have this strongly defined a list. The start and end character will only search for those three strings.

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Use:

/@(foo|bar|baz)\.?$/i

Note the differences from other answers:

\.? - matching 0 or 1 dots, in case the domains in the e-mail address are "fully qualified"
$ - to indicate that the string must end with this sequence,
/i - to make the test case insensitive.

Note, this assumes that each e-mail address is on a line on its own.

If the string being matched could be anywhere in the string, then drop the $, and replace it with \s+ (which matches one or more white space characters)

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If the previous (and logical) answers about '|' don't suit you, have a look at

http://metacpan.org/pod/Regex::PreSuf

module description : create regular expressions from word lists

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You don't need a regex to find whether a string contains at least one of a given list of substrings. In Python:

def contain(string_, substrings):
return any(s in string_ for s in substrings)

The above is slow for a large string_ and many substrings. GNU fgrep can efficiently search for multiple patterns at the same time.

Using regex

import re


def contain(string_, substrings):
regex = '|'.join("(?:%s)" % re.escape(s) for s in substrings)
return re.search(regex, string_) is not None

正则表达式检测多个字符串之一

Using regex

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