如何获取整数格式的 NSDate 日期、月份和年份？

小开

Here you are,

NSDate *currentDate = [NSDate date];
NSCalendar* calendar = [NSCalendar currentCalendar];
NSDateComponents* components = [calendar components:NSCalendarUnitYear|NSCalendarUnitMonth|NSCalendarUnitDay fromDate:currentDate]; // Get necessary date components


[components month]; //gives you month
[components day]; //gives you day
[components year]; // gives you year

You can use NSDateComponents for that as above.

Please visit this page for details.

小开

Yes by the use of NSCalendar, though, i think this will make your work.

NSDateComponents *components = [[NSCalendar currentCalendar] components:NSDayCalendarUnit | NSMonthCalendarUnit | NSYearCalendarUnit fromDate:[NSDate date]];
NSInteger day = [components day];
NSInteger month = [components month];
NSInteger year = [components year];

小开

You can use NSDateComponents to get this,

NSCalendar *calendar = [NSCalendar autoupdatingCurrentCalendar];
NSDate *currDate = [NSDate date];
NSDateComponents *dComp = [calendar components:( NSYearCalendarUnit | NSMonthCalendarUnit |  NSDayCalendarUnit )
fromDate:currDate];


int day = [dComp day];
int month = [dComp month];
int year = [dComp year];

小开

U can try this .......

Mycal = [NSCalendar currentCalendar];
today = [NSDate date];
compA =[Mycal components:(NSMonthCalendarUnit | NSDayCalendarUnit | NSYearCalendarUnit | NSWeekdayCalendarUnit) fromDate:today];
FirstDateofMonth=[today dateByAddingTimeInterval:([compA day]-1)*(-24*60*60)];


compA =[Mycal components:(NSMonthCalendarUnit | NSDayCalendarUnit | NSYearCalendarUnit | NSWeekdayCalendarUnit) fromDate:FirstDateofMonth];
today = FirstDateofMonth;
compA = [Mycal components:(NSMonthCalendarUnit | NSDayCalendarUnit | NSYearCalendarUnit | NSWeekdayCalendarUnit) fromDate:today];
[compA setMonth:([compA month])];
[self DrawMonthInPortraitView];
[compA retain];

小开

To those who just copy and paste directly from the web, like me, this is a small update for iOS 8

NSCalendar* calendar = [NSCalendar currentCalendar];
NSDateComponents* components = [calendar components:NSCalendarUnitYear|NSCalendarUnitMonth|NSCalendarUnitDay fromDate:[NSDate date]];
[components day]; //Day
[components month];//Month
[components year];//Year

小开

NSDate *currentDate = [NSDate date];
NSCalendar* calendar = [NSCalendar currentCalendar];
NSDateComponents* components = [calendar components:NSYearCalendarUnit|NSMonthCalendarUnit|NSDayCalendarUnit fromDate:currentDate]; // Get necessary date components


[components month]; //gives you month
[components day]; //gives you day
[components year]; // gives you year


NSString *temp=[NSString stringWithFormat:@"Months:%d Day:%d Year:%d",[components month],  [components day],[components year]];
NSLog(@"%@",temp);

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最佳答案

Swift

let components = NSCalendar.currentCalendar().components([.Day, .Month, .Year], fromDate: self)
let day = components.day
let month = components.month
let year = components.year

For convenience you can put this in an NSDate extension and make it return a tuple:

extension NSDate: Comparable {


var dayMonthYear: (Int, Int, Int) {
let components = NSCalendar.currentCalendar().components([.Day, .Month, .Year], fromDate: self)
return (components.day, components.month, components.year)
}
}

Now you have to write only:

let (day, month, year) = date.dayMonthYear

If you wanted to e.g. get only the the year you can write:

let (_, _, year) = date.dayMonthYear

小开

let date = Date()
let calendar = Calendar.current


let year = calendar.component(.year, from: date)
let month = calendar.component(.month, from: date)
let day = calendar.component(.day, from: date)
print("hours = \(year):\(month):\(day)")

小开

Put it in an extension and live your life 🍸🏖

extension Date{
var day:Int {return Calendar.current.component(.day, from:self)}
var month:Int {return Calendar.current.component(.month, from:self)}
var year:Int {return Calendar.current.component(.year, from:self)}
}
Date().day//22
Date().month//4
Date().year//2017

Swift 3.0 (It's an iteration of previous answers, but solves it for all your future app projects)