将数据附加到 POSTNSULRequest

如何将数据追加到现有的 POST NSURLRequest? 我需要添加一个新的参数 userId=2323

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 NSURL *url= [NSURL URLWithString:@"https://www.paypal.com/cgi-bin/webscr"];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:aUrl
cachePolicy:NSURLRequestUseProtocolCachePolicy
timeoutInterval:10.0];
[request setHTTPMethod:@"POST"];
NSString *postString = @"userId=2323";
[request setHTTPBody:[postString dataUsingEncoding:NSUTF8StringEncoding]];

If you don't wish to use 3rd party classes then the following is how you set the post body...

NSURL *aUrl = [NSURL URLWithString:@"http://www.apple.com/"];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:aUrl
cachePolicy:NSURLRequestUseProtocolCachePolicy
timeoutInterval:60.0];


[request setHTTPMethod:@"POST"];
NSString *postString = @"company=Locassa&quality=AWESOME!";
[request setHTTPBody:[postString dataUsingEncoding:NSUTF8StringEncoding]];


NSURLConnection *connection= [[NSURLConnection alloc] initWithRequest:request
delegate:self];

Simply append your key/value pair to the post string

The example code above was really helpful to me, however (as has been hinted at above), I think you need to use NSMutableURLRequest rather than NSURLRequest. In its current form, I couldn't get it to respond to the setHTTPMethod call. Changing the type fixed things right up.

All the changes to the NSMutableURLRequest must be made before calling NSURLConnection.

I see this problem as I copy and paste the code above and run TCPMon and see the request is GET instead of the expected POST.

NSURL *aUrl = [NSURL URLWithString:@"http://www.apple.com/"];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:aUrl
cachePolicy:NSURLRequestUseProtocolCachePolicy
timeoutInterval:60.0];




[request setHTTPMethod:@"POST"];
NSString *postString = @"company=Locassa&quality=AWESOME!";
[request setHTTPBody:[postString dataUsingEncoding:NSUTF8StringEncoding]];


NSURLConnection *connection= [[NSURLConnection alloc] initWithRequest:request
delegate:self];

The previous posts about forming POST requests are largely correct (add the parameters to the body, not the URL). But if there is any chance of the input data containing any reserved characters (e.g. spaces, ampersand, plus sign), then you will want to handle these reserved characters. Namely, you should percent-escape the input.

//create body of the request


NSString *userid = ...
NSString *encodedUserid = [self percentEscapeString:userid];
NSString *postString    = [NSString stringWithFormat:@"userid=%@", encodedUserid];
NSData   *postBody      = [postString dataUsingEncoding:NSUTF8StringEncoding];


//initialize a request from url


NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
[request setHTTPBody:postBody];
[request setHTTPMethod:@"POST"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];


//initialize a connection from request, any way you want to, e.g.


NSURLConnection *connection = [[NSURLConnection alloc] initWithRequest:request delegate:self];

Where the precentEscapeString method is defined as follows:

- (NSString *)percentEscapeString:(NSString *)string
{
NSString *result = CFBridgingRelease(CFURLCreateStringByAddingPercentEscapes(kCFAllocatorDefault,
(CFStringRef)string,
(CFStringRef)@" ",
(CFStringRef)@":/?@!$&'()*+,;=",
kCFStringEncodingUTF8));
return [result stringByReplacingOccurrencesOfString:@" " withString:@"+"];
}

Note, there was a promising NSString method, stringByAddingPercentEscapesUsingEncoding (now deprecated), that does something very similar, but resist the temptation to use that. It handles some characters (e.g. the space character), but not some of the others (e.g. the + or & characters).

The contemporary equivalent is stringByAddingPercentEncodingWithAllowedCharacters, but, again, don't be tempted to use URLQueryAllowedCharacterSet, as that also allows + and & pass unescaped. Those two characters are permitted within the broader "query", but if those characters appear within a value within a query, they must escaped. Technically, you can either use URLQueryAllowedCharacterSet to build a mutable character set and remove a few of the characters that they've included in there, or build your own character set from scratch.

For example, if you look at Alamofire's #3, they take URLQueryAllowedCharacterSet and then remove generalDelimitersToEncode (which includes the characters #, [, ], and @, but because of a historical bug in some old web servers, neither ? nor /) and subDelimitersToEncode (i.e. !, generalDelimitersToEncode0, generalDelimitersToEncode1, generalDelimitersToEncode2, generalDelimitersToEncode3, generalDelimitersToEncode4, generalDelimitersToEncode5, generalDelimitersToEncode6, generalDelimitersToEncode7, generalDelimitersToEncode8, and generalDelimitersToEncode9). This is correct implementation (though you could debate the removal of ? and /), though pretty convoluted. Perhaps #2 is more direct/efficient.

Any one looking for a swift solution

let url = NSURL(string: "http://www.apple.com/")
let request = NSMutableURLRequest(URL: url!)
request.HTTPBody = "company=Locassa&quality=AWESOME!".dataUsingEncoding(NSUTF8StringEncoding)