有字符串的方式。替换只点击“整个单词”

A regex is the easiest approach:

string input = "test, and test but not testing.  But yes to test";
string pattern = @"\btest\b";
string replace = "text";
string result = Regex.Replace(input, pattern, replace);
Console.WriteLine(result);

The important part of the pattern is the \b metacharacter, which matches on word boundaries. If you need it to be case-insensitive use RegexOptions.IgnoreCase:

Regex.Replace(input, pattern, replace, RegexOptions.IgnoreCase);

I've created a function (see blog post here) that wraps regex expression, suggested by Ahmad Mageed

/// <summary>
/// Uses regex '\b' as suggested in https://stackoverflow.com/questions/6143642/way-to-have-string-replace-only-hit-whole-words
/// </summary>
/// <param name="original"></param>
/// <param name="wordToFind"></param>
/// <param name="replacement"></param>
/// <param name="regexOptions"></param>
/// <returns></returns>
static public string ReplaceWholeWord(this string original, string wordToFind, string replacement, RegexOptions regexOptions = RegexOptions.None)
{
string pattern = String.Format(@"\b{0}\b", wordToFind);
string ret=Regex.Replace(original, pattern, replacement, regexOptions);
return ret;
}

I just want to add a note about this particular regex pattern (used both in the accepted answer and in ReplaceWholeWord function). It doesn't work if what you are trying to replace isn't a word.

Here a test case:

using System;
using System.Text.RegularExpressions;
public class Test
{
public static void Main()
{
string input = "doin' some replacement";
string pattern = @"\bdoin'\b";
string replace = "doing";
string result = Regex.Replace(input, pattern, replace);
Console.WriteLine(result);
}
}

(ready to try code: http://ideone.com/2Nt0A)

This has to be taken into consideration especially if you are doing batch translations (like I did for some i18n work).

As commented by Sga, the regex solution isn't perfect. And I guess not performance friendly too.

Here is my contribution :

public static class StringExtendsionsMethods
{
public static String ReplaceWholeWord ( this String s, String word, String bywhat )
{
char firstLetter = word[0];
StringBuilder sb = new StringBuilder();
bool previousWasLetterOrDigit = false;
int i = 0;
while ( i < s.Length - word.Length + 1 )
{
bool wordFound = false;
char c = s[i];
if ( c == firstLetter )
if ( ! previousWasLetterOrDigit )
if ( s.Substring ( i, word.Length ).Equals ( word ) )
{
wordFound = true;
bool wholeWordFound = true;
if ( s.Length > i + word.Length )
{
if ( Char.IsLetterOrDigit ( s[i+word.Length] ) )
wholeWordFound = false;
}


if ( wholeWordFound )
sb.Append ( bywhat );
else
sb.Append ( word );


i += word.Length;
}


if ( ! wordFound )
{
previousWasLetterOrDigit = Char.IsLetterOrDigit ( c );
sb.Append ( c );
i++;
}
}


if ( s.Length - i > 0 )
sb.Append ( s.Substring ( i ) );


return sb.ToString ();
}
}

With test cases :

String a = "alpha is alpha";
Console.WriteLine ( a.ReplaceWholeWord ( "alpha", "alphonse" ) );
Console.WriteLine ( a.ReplaceWholeWord ( "alpha", "alf" ) );


a = "alphaisomega";
Console.WriteLine ( a.ReplaceWholeWord ( "alpha", "xxx" ) );


a = "aalpha is alphaa";
Console.WriteLine ( a.ReplaceWholeWord ( "alpha", "xxx" ) );


a = "alpha1/alpha2/alpha3";
Console.WriteLine ( a.ReplaceWholeWord ( "alpha", "xxx" ) );


a = "alpha/alpha/alpha";
Console.WriteLine ( a.ReplaceWholeWord ( "alpha", "alphonse" ) );

You could use the string.replace

string input = "test, and test but not testing.  But yes to test";
string result2 = input.Replace("test", "text");
Console.WriteLine(input);
Console.WriteLine(result2);
Console.ReadLine();

If you want to define what characters make up a word i.e. "_" and "@"

you could use my (vb.net) function:

 Function Replace_Whole_Word(Input As String, Find As String, Replace As String)
Dim Word_Chars As String = "ABCDEFGHIJKLMNOPQRSTUVWYXZabcdefghijklmnopqrstuvwyxz0123456789_@"
Dim Word_Index As Integer = 0
Do Until False
Word_Index = Input.IndexOf(Find, Word_Index)
If Word_Index < 0 Then Exit Do
If Word_Index = 0 OrElse Word_Chars.Contains(Input(Word_Index - 1)) = False Then
If Word_Index + Len(Find) = Input.Length OrElse Word_Chars.Contains(Input(Word_Index + Len(Find))) = False Then
Input = Mid(Input, 1, Word_Index) & Replace & Mid(Input, Word_Index + Len(Find) + 1)
End If
End If
Word_Index = Word_Index + 1
Loop
Return Input
End Function

Test

Replace_Whole_Word("We need to replace words tonight. Not to_day and not too well to", "to", "xxx")

Result

"We need xxx replace words tonight. Not to_day and not too well xxx"

I don't like Regex because it is slow. My function is faster.

public static string ReplaceWholeWord(this string text, string word, string bywhat)
{
static bool IsWordChar(char c) => char.IsLetterOrDigit(c) || c == '_';
StringBuilder sb = null;
int p = 0, j = 0;
while (j < text.Length && (j = text.IndexOf(word, j, StringComparison.Ordinal)) >= 0)
if ((j == 0 || !IsWordChar(text[j - 1])) &&
(j + word.Length == text.Length || !IsWordChar(text[j + word.Length])))
{
sb ??= new StringBuilder();
sb.Append(text, p, j - p);
sb.Append(bywhat);
j += word.Length;
p = j;
}
else j++;
if (sb == null) return text;
sb.Append(text, p, text.Length - p);
return sb.ToString();
}

This method also ignores the case if you are interested

public static string Replace(this string s, string word, string by, StringComparison stringComparison, bool WholeWord)
{
s = s + " ";
int wordSt;
StringBuilder sb = new StringBuilder();
while (s.IndexOf(word, stringComparison) > -1)
{
wordSt = s.IndexOf(word, stringComparison);
if (!WholeWord || ((wordSt == 0 || !Char.IsLetterOrDigit(char.Parse(s.Substring(wordSt - 1, 1)))) && !Char.IsLetterOrDigit(char.Parse(s.Substring(wordSt + word.Length, 1)))))
{
sb.Append(s.Substring(0, wordSt) + by);
}
else
{
sb.Append(s.Substring(0, wordSt + word.Length));
}
s = s.Substring(wordSt + word.Length);
}
sb.Append(s);
return sb.ToString().Substring(0, sb.Length - 1);
}