仅匹配字母字符的正则表达式

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This will match one or more alphabetical characters:

/^[a-z]+$/

You can make it case insensitive using:

/^[a-z]+$/i

or:

/^[a-zA-Z]+$/

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最佳答案

You may use any of these 2 variants:

/^[A-Z]+$/i
/^[A-Za-z]+$/

to match an input string of ASCII alphabets.

[A-Za-z] will match all the alphabets (both lowercase and uppercase).
^ and $ will make sure that nothing but these alphabets will be matched.

Code:

preg_match('/^[A-Z]+$/i', "abcAbc^Xyz", $m);
var_dump($m);

Output:

array(0) {
}

Test case is for OP's comment that he wants to match only if there are 1 or more alphabets present in the input. As you can see in the test case that matches failed because there was ^ in the input string abcAbc^Xyz.

Note: Please note that the above answer only matches ASCII alphabets and doesn't match Unicode characters. If you want to match Unicode letters then use:

/^\p{L}+$/u

Here, \p{L} matches any kind of letter from any language

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[a-zA-Z] should do that just fine.

You can reference the cheat sheet.

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If you need to include non-ASCII alphabetic characters, and if your regex flavor supports Unicode, then

\A\pL+\z

would be the correct regex.

Some regex engines don't support this Unicode syntax but allow the \w alphanumeric shorthand to also match non-ASCII characters. In that case, you can get all alphabetics by subtracting digits and underscores from \w like this:

\A[^\W\d_]+\z

\A matches at the start of the string, \z at the end of the string (^ and $ also match at the start/end of lines in some languages like Ruby, or if certain regex options are set).

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In Ruby and other languages that support POSIX character classes in bracket expressions, you can do simply:

/\A[[:alpha:]]+\z/i

That will match alpha-chars in all Unicode alphabet languages. Easy peasy.

More info: http://en.wikipedia.org/wiki/Regular_expression#Character_classes http://ruby-doc.org/core-2.0/Regexp.html