使用PHP打印漂亮的JSON

我正在构建一个将JSON数据提供给另一个脚本的PHP脚本。我的脚本将数据构建到一个大型关联数组中,然后使用json_encode输出数据。这是一个示例脚本:

$data = array('a' => 'apple', 'b' => 'banana', 'c' => 'catnip');
header('Content-type: text/javascript');
echo json_encode($data);

上面的代码产生以下输出:

{"a":"apple","b":"banana","c":"catnip"}

如果你有少量的数据,这很好,但我更喜欢这样的东西:

{
"a": "apple",
"b": "banana",
"c": "catnip"
}

有没有办法在PHP中做到这一点而不会出现丑陋的黑客攻击?似乎facebook的某个人想出了办法。

761305 次浏览

如果您使用的是火狐安装JSONovich。我知道这不是一个真正的PHP解决方案,但它确实可以用于开发目的/调试。

我也有同样的问题。

无论如何,我只是在这里使用json格式代码:

http://recursive-design.com/blog/2008/03/11/format-json-with-php/

工作得很好,我需要它。

还有一个更维护的版本:https://github.com/GerHobbelt/nicejson-php

PHP 5.4提供了JSON_PRETTY_PRINT选项,用于json_encode()调用。

https://php.net/manual/en/function.json-encode.php

<?php
...
$json_string = json_encode($data, JSON_PRETTY_PRINT);

这个函数将采用JSON字符串并缩进它非常可读。它也应该是收敛的,

prettyPrint( $json ) === prettyPrint( prettyPrint( $json ) )

输入

{"key1":[1,2,3],"key2":"value"}

产出

{
"key1": [
1,
2,
3
],
"key2": "value"
}

代码

function prettyPrint( $json )
{
$result = '';
$level = 0;
$in_quotes = false;
$in_escape = false;
$ends_line_level = NULL;
$json_length = strlen( $json );


for( $i = 0; $i < $json_length; $i++ ) {
$char = $json[$i];
$new_line_level = NULL;
$post = "";
if( $ends_line_level !== NULL ) {
$new_line_level = $ends_line_level;
$ends_line_level = NULL;
}
if ( $in_escape ) {
$in_escape = false;
} else if( $char === '"' ) {
$in_quotes = !$in_quotes;
} else if( ! $in_quotes ) {
switch( $char ) {
case '}': case ']':
$level--;
$ends_line_level = NULL;
$new_line_level = $level;
break;


case '{': case '[':
$level++;
case ',':
$ends_line_level = $level;
break;


case ':':
$post = " ";
break;


case " ": case "\t": case "\n": case "\r":
$char = "";
$ends_line_level = $new_line_level;
$new_line_level = NULL;
break;
}
} else if ( $char === '\\' ) {
$in_escape = true;
}
if( $new_line_level !== NULL ) {
$result .= "\n".str_repeat( "\t", $new_line_level );
}
$result .= $char.$post;
}


return $result;
}

如果您正在使用MVC

尝试在您的控制器中执行此操作

public function getLatestUsers() {
header('Content-Type: application/json');
echo $this->model->getLatestUsers(); // this returns json_encode($somedata, JSON_PRETTY_PRINT)
}

然后如果你调用 /getLatestUsers你会得到一个漂亮的JSON输出;)

以下是对我有用的:

test.php内容:

<html>
<body>
Testing JSON array output
<pre>
<?php
$data = array('a'=>'apple', 'b'=>'banana', 'c'=>'catnip');
// encode in json format
$data = json_encode($data);


// json as single line
echo "</br>Json as single line </br>";
echo $data;
// json as an array, formatted nicely
echo "</br>Json as multiline array </br>";
print_r(json_decode($data, true));
?>
</pre>
</body>
</html>

输出:

Testing JSON array output




Json as single line
{"a":"apple","b":"banana","c":"catnip"}
Json as multiline array
Array
(
[a] => apple
[b] => banana
[c] => catnip
)

还要注意在html中使用“pre-”标签。

希望能帮到别人

你可以像下面这样做。

$array = array(
"a" => "apple",
"b" => "banana",
"c" => "catnip"
);


foreach ($array as $a_key => $a_val) {
$json .= "\"{$a_key}\" : \"{$a_val}\",\n";
}


header('Content-Type: application/json');
echo "{\n"  .rtrim($json, ",\n") . "\n}";

上面的输出有点像Facebook。

{
"a" : "apple",
"b" : "banana",
"c" : "catnip"
}

具有彩色全输出:Tiny Solution

代码:

$s = '{"access": {"token": {"issued_at": "2008-08-16T14:10:31.309353", "expires": "2008-08-17T14:10:31Z", "id": "MIICQgYJKoZIhvcIegeyJpc3N1ZWRfYXQiOiAi"}, "serviceCatalog": [], "user": {"username": "ajay", "roles_links": [], "id": "16452ca89", "roles": [], "name": "ajay"}}}';


$crl = 0;
$ss = false;
echo "<pre>";
for($c=0; $c<strlen($s); $c++)
{
if ( $s[$c] == '}' || $s[$c] == ']' )
{
$crl--;
echo "\n";
echo str_repeat(' ', ($crl*2));
}
if ( $s[$c] == '"' && ($s[$c-1] == ',' || $s[$c-2] == ',') )
{
echo "\n";
echo str_repeat(' ', ($crl*2));
}
if ( $s[$c] == '"' && !$ss )
{
if ( $s[$c-1] == ':' || $s[$c-2] == ':' )
echo '<span style="color:#0000ff;">';
else
echo '<span style="color:#ff0000;">';
}
echo $s[$c];
if ( $s[$c] == '"' && $ss )
echo '</span>';
if ( $s[$c] == '"' )
$ss = !$ss;
if ( $s[$c] == '{' || $s[$c] == '[' )
{
$crl++;
echo "\n";
echo str_repeat(' ', ($crl*2));
}
}
echo $s[$c];

我从Composer中获取代码:https://github.com/composer/composer/blob/master/src/Composer/Json/JsonFile.php和nicejson:https://github.com/GerHobbelt/nicejson-php/blob/master/nicejson.php Composer代码很好,因为它可以从5.3流畅地更新到5.4,但它只编码对象,而nicejson需要json字符串,所以我合并了它们。该代码可用于格式化json字符串和/或编码对象,我目前正在Drupal模块中使用它。

if (!defined('JSON_UNESCAPED_SLASHES'))
define('JSON_UNESCAPED_SLASHES', 64);
if (!defined('JSON_PRETTY_PRINT'))
define('JSON_PRETTY_PRINT', 128);
if (!defined('JSON_UNESCAPED_UNICODE'))
define('JSON_UNESCAPED_UNICODE', 256);


function _json_encode($data, $options = 448)
{
if (version_compare(PHP_VERSION, '5.4', '>='))
{
return json_encode($data, $options);
}


return _json_format(json_encode($data), $options);
}


function _pretty_print_json($json)
{
return _json_format($json, JSON_PRETTY_PRINT);
}


function _json_format($json, $options = 448)
{
$prettyPrint = (bool) ($options & JSON_PRETTY_PRINT);
$unescapeUnicode = (bool) ($options & JSON_UNESCAPED_UNICODE);
$unescapeSlashes = (bool) ($options & JSON_UNESCAPED_SLASHES);


if (!$prettyPrint && !$unescapeUnicode && !$unescapeSlashes)
{
return $json;
}


$result = '';
$pos = 0;
$strLen = strlen($json);
$indentStr = ' ';
$newLine = "\n";
$outOfQuotes = true;
$buffer = '';
$noescape = true;


for ($i = 0; $i < $strLen; $i++)
{
// Grab the next character in the string
$char = substr($json, $i, 1);


// Are we inside a quoted string?
if ('"' === $char && $noescape)
{
$outOfQuotes = !$outOfQuotes;
}


if (!$outOfQuotes)
{
$buffer .= $char;
$noescape = '\\' === $char ? !$noescape : true;
continue;
}
elseif ('' !== $buffer)
{
if ($unescapeSlashes)
{
$buffer = str_replace('\\/', '/', $buffer);
}


if ($unescapeUnicode && function_exists('mb_convert_encoding'))
{
// http://stackoverflow.com/questions/2934563/how-to-decode-unicode-escape-sequences-like-u00ed-to-proper-utf-8-encoded-cha
$buffer = preg_replace_callback('/\\\\u([0-9a-f]{4})/i',
function ($match)
{
return mb_convert_encoding(pack('H*', $match[1]), 'UTF-8', 'UCS-2BE');
}, $buffer);
}


$result .= $buffer . $char;
$buffer = '';
continue;
}
elseif(false !== strpos(" \t\r\n", $char))
{
continue;
}


if (':' === $char)
{
// Add a space after the : character
$char .= ' ';
}
elseif (('}' === $char || ']' === $char))
{
$pos--;
$prevChar = substr($json, $i - 1, 1);


if ('{' !== $prevChar && '[' !== $prevChar)
{
// If this character is the end of an element,
// output a new line and indent the next line
$result .= $newLine;
for ($j = 0; $j < $pos; $j++)
{
$result .= $indentStr;
}
}
else
{
// Collapse empty {} and []
$result = rtrim($result) . "\n\n" . $indentStr;
}
}


$result .= $char;


// If the last character was the beginning of an element,
// output a new line and indent the next line
if (',' === $char || '{' === $char || '[' === $char)
{
$result .= $newLine;


if ('{' === $char || '[' === $char)
{
$pos++;
}


for ($j = 0; $j < $pos; $j++)
{
$result .= $indentStr;
}
}
}
// If buffer not empty after formating we have an unclosed quote
if (strlen($buffer) > 0)
{
//json is incorrectly formatted
$result = false;
}


return $result;
}

如果你只使用$json_string = json_encode($data, JSON_PRETTY_PRINT);,你会在浏览器中得到这样的东西(使用问题中的facebook链接:): 在此处输入图片描述

如果您使用像JSONView这样的Chrome扩展(即使没有上面的PHP选项),那么您将获得更多非常易读可调试的解决方案,您甚至可以像这样轻松折叠/折叠每个JSON对象: 在此处输入图片描述

您可以在Switch语句中稍微修改Kendall Hopkins的答案,以通过将json字符串传递到以下内容来获得非常干净的外观和良好的缩进打印输出:

function prettyPrint( $json ){


$result = '';
$level = 0;
$in_quotes = false;
$in_escape = false;
$ends_line_level = NULL;
$json_length = strlen( $json );


for( $i = 0; $i < $json_length; $i++ ) {
$char = $json[$i];
$new_line_level = NULL;
$post = "";
if( $ends_line_level !== NULL ) {
$new_line_level = $ends_line_level;
$ends_line_level = NULL;
}
if ( $in_escape ) {
$in_escape = false;
} else if( $char === '"' ) {
$in_quotes = !$in_quotes;
} else if( ! $in_quotes ) {
switch( $char ) {
case '}': case ']':
$level--;
$ends_line_level = NULL;
$new_line_level = $level;
$char.="<br>";
for($index=0;$index<$level-1;$index++){$char.="-----";}
break;


case '{': case '[':
$level++;
$char.="<br>";
for($index=0;$index<$level;$index++){$char.="-----";}
break;
case ',':
$ends_line_level = $level;
$char.="<br>";
for($index=0;$index<$level;$index++){$char.="-----";}
break;


case ':':
$post = " ";
break;


case "\t": case "\n": case "\r":
$char = "";
$ends_line_level = $new_line_level;
$new_line_level = NULL;
break;
}
} else if ( $char === '\\' ) {
$in_escape = true;
}
if( $new_line_level !== NULL ) {
$result .= "\n".str_repeat( "\t", $new_line_level );
}
$result .= $char.$post;
}


echo "RESULTS ARE: <br><br>$result";
return $result;

}

现在只需在你的php中运行函数,并享受打印输出。如果你是一个极简主义者,并且出于某种原因不喜欢括号,你可以通过将$char上前三个开关案例中的$char.="<br>";替换为$char="<br>";来轻松摆脱这些括号。这是你为卡尔加里市的谷歌地图API调用得到的

RESULTS ARE:


{
- - - "results" : [
- - -- - - {
- - -- - -- - - "address_components" : [
- - -- - -- - -- - - {
- - -- - -- - -- - -- - - "long_name" : "Calgary"
- - -- - -- - -- - -- - - "short_name" : "Calgary"
- - -- - -- - -- - -- - - "types" : [
- - -- - -- - -- - -- - -- - - "locality"
- - -- - -- - -- - -- - -- - - "political" ]
- - -- - -- - -- - - }
- - -- - -- - -
- - -- - -- - -- - - {
- - -- - -- - -- - -- - - "long_name" : "Division No. 6"
- - -- - -- - -- - -- - - "short_name" : "Division No. 6"
- - -- - -- - -- - -- - - "types" : [
- - -- - -- - -- - -- - -- - - "administrative_area_level_2"
- - -- - -- - -- - -- - -- - - "political" ]
- - -- - -- - -- - - }
- - -- - -- - -
- - -- - -- - -- - - {
- - -- - -- - -- - -- - - "long_name" : "Alberta"
- - -- - -- - -- - -- - - "short_name" : "AB"
- - -- - -- - -- - -- - - "types" : [
- - -- - -- - -- - -- - -- - - "administrative_area_level_1"
- - -- - -- - -- - -- - -- - - "political" ]
- - -- - -- - -- - - }
- - -- - -- - -
- - -- - -- - -- - - {
- - -- - -- - -- - -- - - "long_name" : "Canada"
- - -- - -- - -- - -- - - "short_name" : "CA"
- - -- - -- - -- - -- - - "types" : [
- - -- - -- - -- - -- - -- - - "country"
- - -- - -- - -- - -- - -- - - "political" ]
- - -- - -- - -- - - }
- - -- - -- - - ]
- - -- - -
- - -- - -- - - "formatted_address" : "Calgary, AB, Canada"
- - -- - -- - - "geometry" : {
- - -- - -- - -- - - "bounds" : {
- - -- - -- - -- - -- - - "northeast" : {
- - -- - -- - -- - -- - -- - - "lat" : 51.18383
- - -- - -- - -- - -- - -- - - "lng" : -113.8769511 }
- - -- - -- - -- - -
- - -- - -- - -- - -- - - "southwest" : {
- - -- - -- - -- - -- - -- - - "lat" : 50.84240399999999
- - -- - -- - -- - -- - -- - - "lng" : -114.27136 }
- - -- - -- - -- - - }
- - -- - -- - -
- - -- - -- - -- - - "location" : {
- - -- - -- - -- - -- - - "lat" : 51.0486151
- - -- - -- - -- - -- - - "lng" : -114.0708459 }
- - -- - -- - -
- - -- - -- - -- - - "location_type" : "APPROXIMATE"
- - -- - -- - -- - - "viewport" : {
- - -- - -- - -- - -- - - "northeast" : {
- - -- - -- - -- - -- - -- - - "lat" : 51.18383
- - -- - -- - -- - -- - -- - - "lng" : -113.8769511 }
- - -- - -- - -- - -
- - -- - -- - -- - -- - - "southwest" : {
- - -- - -- - -- - -- - -- - - "lat" : 50.84240399999999
- - -- - -- - -- - -- - -- - - "lng" : -114.27136 }
- - -- - -- - -- - - }
- - -- - -- - - }
- - -- - -
- - -- - -- - - "place_id" : "ChIJ1T-EnwNwcVMROrZStrE7bSY"
- - -- - -- - - "types" : [
- - -- - -- - -- - - "locality"
- - -- - -- - -- - - "political" ]
- - -- - - }
- - - ]


- - - "status" : "OK" }

PHP>5.4的简单方法:就像Facebook图一样

$Data = array('a' => 'apple', 'b' => 'banana', 'c' => 'catnip');
$json= json_encode($Data, JSON_PRETTY_PRINT);
header('Content-Type: application/json');
print_r($json);

结果在浏览器中

{
"a": "apple",
"b": "banana",
"c": "catnip"
}

递归解决方案的经典案例。这是我的:

class JsonFormatter {
public static function prettyPrint(&$j, $indentor = "\t", $indent = "") {
$inString = $escaped = false;
$result = $indent;


if(is_string($j)) {
$bak = $j;
$j = str_split(trim($j, '"'));
}


while(count($j)) {
$c = array_shift($j);
if(false !== strpos("{[,]}", $c)) {
if($inString) {
$result .= $c;
} else if($c == '{' || $c == '[') {
$result .= $c."\n";
$result .= self::prettyPrint($j, $indentor, $indentor.$indent);
$result .= $indent.array_shift($j);
} else if($c == '}' || $c == ']') {
array_unshift($j, $c);
$result .= "\n";
return $result;
} else {
$result .= $c."\n".$indent;
}
} else {
$result .= $c;
$c == '"' && !$escaped && $inString = !$inString;
$escaped = $c == '\\' ? !$escaped : false;
}
}


$j = $bak;
return $result;
}
}

用法:

php > require 'JsonFormatter.php';
php > $a = array('foo' => 1, 'bar' => 'This "is" bar', 'baz' => array('a' => 1, 'b' => 2, 'c' => '"3"'));
php > print_r($a);
Array
(
[foo] => 1
[bar] => This "is" bar
[baz] => Array
(
[a] => 1
[b] => 2
[c] => "3"
)


)
php > echo JsonFormatter::prettyPrint(json_encode($a));
{
"foo":1,
"bar":"This \"is\" bar",
"baz":{
"a":1,
"b":2,
"c":"\"3\""
}
}

干杯

我意识到这个问题是关于如何将关联数组编码为格式漂亮的JSON字符串,所以这并不能直接回答这个问题,但是如果你有一个已经是JSON格式的字符串,你可以通过解码和重新编码来使它变得漂亮(需要PHP>=5.4):

$json = json_encode(json_decode($json), JSON_PRETTY_PRINT);

示例:

header('Content-Type: application/json');
$json_ugly = '{"a":1,"b":2,"c":3,"d":4,"e":5}';
$json_pretty = json_encode(json_decode($json_ugly), JSON_PRETTY_PRINT);
echo $json_pretty;

此输出:

{
"a": 1,
"b": 2,
"c": 3,
"d": 4,
"e": 5
}

<pre>json_encode()JSON_PRETTY_PRINT选项结合使用:

<pre>
<?php
echo json_encode($dataArray, JSON_PRETTY_PRINT);
?>
</pre>

print_r漂亮的PHP打印

PHP示例

function print_nice($elem,$max_level=10,$print_nice_stack=array()){
if(is_array($elem) || is_object($elem)){
if(in_array($elem,$print_nice_stack,true)){
echo "<font color=red>RECURSION</font>";
return;
}
$print_nice_stack[]=&$elem;
if($max_level<1){
echo "<font color=red>nivel maximo alcanzado</font>";
return;
}
$max_level--;
echo "<table border=1 cellspacing=0 cellpadding=3 width=100%>";
if(is_array($elem)){
echo '<tr><td colspan=2 style="background-color:#333333;"><strong><font color=white>ARRAY</font></strong></td></tr>';
}else{
echo '<tr><td colspan=2 style="background-color:#333333;"><strong>';
echo '<font color=white>OBJECT Type: '.get_class($elem).'</font></strong></td></tr>';
}
$color=0;
foreach($elem as $k => $v){
if($max_level%2){
$rgb=($color++%2)?"#888888":"#BBBBBB";
}else{
$rgb=($color++%2)?"#8888BB":"#BBBBFF";
}
echo '<tr><td valign="top" style="width:40px;background-color:'.$rgb.';">';
echo '<strong>'.$k."</strong></td><td>";
print_nice($v,$max_level,$print_nice_stack);
echo "</td></tr>";
}
echo "</table>";
return;
}
if($elem === null){
echo "<font color=green>NULL</font>";
}elseif($elem === 0){
echo "0";
}elseif($elem === true){
echo "<font color=green>TRUE</font>";
}elseif($elem === false){
echo "<font color=green>FALSE</font>";
}elseif($elem === ""){
echo "<font color=green>EMPTY STRING</font>";
}else{
echo str_replace("\n","<strong><font color=red>*</font></strong><br>\n",$elem);
}
}

许多用户建议您使用

echo json_encode($results, JSON_PRETTY_PRINT);

这是完全正确的。但这还不够,浏览器需要了解数据的类型,您可以在将数据回传给用户之前指定标头。

header('Content-Type: application/json');

这将产生格式良好的输出。

或者,如果您喜欢扩展,您可以使用JSONView进行Chrome。

1-json_encode($rows,JSON_PRETTY_PRINT);返回带有换行符的美化数据。这对命令行输入很有帮助,但正如你所发现的,在浏览器中看起来并不漂亮。浏览器将接受换行符作为源(因此,查看页面源确实会显示漂亮的JSON),但它们不用于在浏览器中格式化输出。浏览器需要超文本标记语言。

2-使用此功能github

<?php
/**
* Formats a JSON string for pretty printing
*
* @param string $json The JSON to make pretty
* @param bool $html Insert nonbreaking spaces and <br />s for tabs and linebreaks
* @return string The prettified output
* @author Jay Roberts
*/
function _format_json($json, $html = false) {
$tabcount = 0;
$result = '';
$inquote = false;
$ignorenext = false;
if ($html) {
$tab = "&nbsp;&nbsp;&nbsp;&nbsp;";
$newline = "<br/>";
} else {
$tab = "\t";
$newline = "\n";
}
for($i = 0; $i < strlen($json); $i++) {
$char = $json[$i];
if ($ignorenext) {
$result .= $char;
$ignorenext = false;
} else {
switch($char) {
case '[':
case '{':
$tabcount++;
$result .= $char . $newline . str_repeat($tab, $tabcount);
break;
case ']':
case '}':
$tabcount--;
$result = trim($result) . $newline . str_repeat($tab, $tabcount) . $char;
break;
case ',':
$result .= $char . $newline . str_repeat($tab, $tabcount);
break;
case '"':
$inquote = !$inquote;
$result .= $char;
break;
case '\\':
if ($inquote) $ignorenext = true;
$result .= $char;
break;
default:
$result .= $char;
}
}
}
return $result;
}

如果您有现有的JSON($ugly_json

echo nl2br(str_replace(' ', '&nbsp;', (json_encode(json_decode($ugly_json), JSON_PRETTY_PRINT | JSON_UNESCAPED_SLASHES))));

这个解决方案使“非常漂亮”的JSON。不完全是OP所要求的,但它可以让您更好地可视化JSON。

/**
* takes an object parameter and returns the pretty json format.
* this is a space saving version that uses 2 spaces instead of the regular 4
*
* @param $in
*
* @return string
*/
function pretty_json ($in): string
{
return preg_replace_callback('/^ +/m',
function (array $matches): string
{
return str_repeat(' ', strlen($matches[0]) / 2);
}, json_encode($in, JSON_PRETTY_PRINT | JSON_HEX_APOS)
);
}


/**
* takes a JSON string an adds colours to the keys/values
* if the string is not JSON then it is returned unaltered.
*
* @param string $in
*
* @return string
*/


function markup_json (string $in): string
{
$string  = 'green';
$number  = 'darkorange';
$null    = 'magenta';
$key     = 'red';
$pattern = '/("(\\\\u[a-zA-Z0-9]{4}|\\\\[^u]|[^\\\\"])*"(\s*:)?|\b(true|false|null)\b|-?\d+(?:\.\d*)?(?:[eE][+\-]?\d+)?)/';
return preg_replace_callback($pattern,
function (array $matches) use ($string, $number, $null, $key): string
{
$match  = $matches[0];
$colour = $number;
if (preg_match('/^"/', $match))
{
$colour = preg_match('/:$/', $match)
? $key
: $string;
}
elseif ($match === 'null')
{
$colour = $null;
}
return "<span style='color:{$colour}'>{$match}</span>";
}, str_replace(['<', '>', '&'], ['&lt;', '&gt;', '&amp;'], $in)
) ?? $in;
}


public function test_pretty_json_object ()
{
$ob       = new \stdClass();
$ob->test = 'unit-tester';
$json     = pretty_json($ob);
$expected = <<<JSON
{
"test": "unit-tester"
}
JSON;
$this->assertEquals($expected, $json);
}


public function test_pretty_json_str ()
{
$ob   = 'unit-tester';
$json = pretty_json($ob);
$this->assertEquals("\"$ob\"", $json);
}


public function test_markup_json ()
{
$json = <<<JSON
[{"name":"abc","id":123,"warnings":[],"errors":null},{"name":"abc"}]
JSON;
$expected = <<<STR
[
{
<span style='color:red'>"name":</span> <span style='color:green'>"abc"</span>,
<span style='color:red'>"id":</span> <span style='color:darkorange'>123</span>,
<span style='color:red'>"warnings":</span> [],
<span style='color:red'>"errors":</span> <span style='color:magenta'>null</span>
},
{
<span style='color:red'>"name":</span> <span style='color:green'>"abc"</span>
}
]
STR;


$output = markup_json(pretty_json(json_decode($json)));
$this->assertEquals($expected,$output);
}

}

将几个答案粘合在一起符合我对现有json:的需求

Code:
echo "<pre>";
echo json_encode(json_decode($json_response), JSON_PRETTY_PRINT);
echo "</pre>";


Output:
{
"data": {
"token_type": "bearer",
"expires_in": 3628799,
"scopes": "full_access",
"created_at": 1540504324
},
"errors": [],
"pagination": {},
"token_type": "bearer",
"expires_in": 3628799,
"scopes": "full_access",
"created_at": 1540504324
}

我用过这个:

echo "<pre>".json_encode($response, JSON_PRETTY_PRINT | JSON_UNESCAPED_UNICODE | JSON_UNESCAPED_SLASHES)."</pre>";

或者使用php头文件,如下所示:

header('Content-type: application/json; charset=UTF-8');
echo json_encode($response, JSON_PRETTY_PRINT | JSON_UNESCAPED_UNICODE | JSON_UNESCAPED_SLASHES);

格式JSON数据的最佳方法是这样的!

header('Content-type: application/json; charset=UTF-8');
echo json_encode($response, JSON_PRETTY_PRINT | JSON_UNESCAPED_UNICODE | JSON_UNESCAPED_SLASHES);

将$响应替换为需要转换为JSON的数据

对于那些运行PHP 5.3或更早版本的人,您可以尝试以下操作:

$pretty_json = "<pre>".print_r(json_decode($json), true)."</pre>";


echo $pretty_json;


这是我自己使用的函数,api就像json_encode,除了它有第三个参数exclude_flags,以防你想排除一些默认标志(如JSON_UNESCAPED_SLASHES)

function json_encode_pretty($data, int $extra_flags = 0, int $exclude_flags = 0): string
{
// prettiest flags for: 7.3.9
$flags = JSON_PRETTY_PRINT | JSON_UNESCAPED_SLASHES | JSON_UNESCAPED_UNICODE | (defined("JSON_UNESCAPED_LINE_TERMINATORS") ? JSON_UNESCAPED_LINE_TERMINATORS : 0) | JSON_PRESERVE_ZERO_FRACTION | (defined("JSON_THROW_ON_ERROR") ? JSON_THROW_ON_ERROR : 0);
$flags = ($flags | $extra_flags) & ~ $exclude_flags;
return (json_encode($data, $flags));
}

更容易提醒:输入128

128是常量“JSON_PRETTY_PRINT”的同义词

PHP文档站点

json_encode($json,128);
//similar to
json_encode($json,JSON_PRETTY_PRINT );

我通常使用这些单行中的一个。

如果你已经有一个JSON字符串,你可以简单地使用echo()print_r()的组合。 不要忘记将print_r()的第二个参数传递给true,以便它返回值而不是打印它:

echo('<pre>' . print_r($json, true) . '</pre>');

或者您可以使用die()进行调试:

die('<pre>' . print_r($json, true) . '</pre>');

如果您有一个数组,则需要将其转换为JSON字符串。 请务必使用JSON_PRETTY_PRINT标志设置json_encode()的第二个参数,以便正确呈现您的JSON:

echo('<pre>' . print_r(json_encode($array, JSON_PRETTY_PRINT), true) . '</pre>');

或用于调试:

die('<pre>' . print_r(json_encode($array, JSON_PRETTY_PRINT), true) . '</pre>');