有没有可能数组列表的和没有循环

Then write it yourself:

public int sum(List<Integer> list) {
int sum = 0;


for (int i : list)
sum = sum + i;


return sum;
}

Given that a list can hold any type of object, there is no built in method which allows you to sum all the elements. You could do something like this:

int sum = 0;


for( Integer i : ( ArrayList<Integer> )tt ) {
sum += i;
}

Alternatively you could create your own container type which inherits from ArrayList but also implements a method called sum() which implements the code above.

Write a util function like

public class ListUtil{


public static int sum(List<Integer> list){
if(list==null || list.size()<1)
return 0;


int sum = 0;
for(Integer i: list)
sum = sum+i;


return sum;
}
}

Then use like

int sum = ListUtil.sum(yourArrayList)

ArrayList is a Collection of elements (in the form of list), primitive are stored as wrapper class object but at the same time i can store objects of String class as well. SUM will not make sense in that. BTW why are so afraid to use for loop (enhanced or through iterator) anyways?

The only alternative to using a loop is to use recursion.

You can define a method like

public static int sum(List<Integer> ints) {
return ints.isEmpty() ? 0 : ints.get(0) + ints.subList(1, ints.length());
}

This is very inefficient compared to using a plain loop and can blow up if you have many elements in the list.

An alternative which avoid a stack overflow is to use.

public static int sum(List<Integer> ints) {
int len = ints.size();
if (len == 0) return 0;
if (len == 1) return ints.get(0);
return sum(ints.subList(0, len/2)) + sum(ints.subList(len/2, len));
}

This is just as inefficient, but will avoid a stack overflow.

The shortest way to write the same thing is

int sum = 0, a[] = {2, 4, 6, 8};


for(int i: a) {
sum += i;
}


System.out.println("sum(a) = " + sum);

prints

sum(a) = 20

Once java-8 is out (March 2014) you'll be able to use streams:

If you have a List<Integer>

int sum = list.stream().mapToInt(Integer::intValue).sum();

If it's an int[]

int sum = IntStream.of(a).sum();

Or switch to Groovy, it has a sum() function on a collection. [1,2,3,4,5,6].sum()

http://groovy.codehaus.org/JN1015-Collections

Runs on the same JVM as your java classes.

This link shows three different ways how to sum in java, there is one option that is not in previous answers using Apache Commons Math..

Example:

public static void main(String args []){
List<Double> NUMBERS_FOR_SUM = new ArrayList<Double>(){
{
add(5D);
add(3.2D);
add(7D);
}
};
double[] arrayToSume = ArrayUtils.toPrimitive(NUMBERS_FOR_SUM
.toArray(new Double[NUMBERS_FOR_SUM.size()]));
System.out.println(StatUtils.sum(arrayToSume));


}

See StatUtils api

You can use apache commons-collections API.

class AggregateClosure implements org.apache.commons.collections.Closure {
int total = 0;


@Override
public void execute(Object input) {
if (input != null) {
total += (Integer) input;
}
}


public int getTotal() {
return total;
}
}

Then use this closure as shown below:

public int aggregate(List<Integer> aList) {
AggregateClosure closure = new AggregateClosure();
org.apache.commons.collections.CollectionUtils.forAllDo(aList, closure);
return closure.getTotal();
}

If you know about the map function, then you know that a map is also can be recursive loop or recursive loop. But obviously you have to reach each element for that. so, I could not work out the Java 8, because some syntax mismatch but wanted a very short so this is what I got.

int sum = 0
for (Integer e : myList) sum += e;

You can use GNU Trove library:

TIntList tt = new TIntArrayList();
tt.add(1);
tt.add(2);
tt.add(3);
int sum = tt.sum();

for me the clearest way is this:

doubleList.stream().reduce((a,b)->a+b).get();

or

doubleList.parallelStream().reduce((a,b)->a+b).get();

It also use internal loops, but it is not possible without loops.

This can be done with reduce using method references reduce(Integer::sum):

Integer reduceSum = Arrays.asList(1, 3, 4, 6, 4)
.stream()
.reduce(Integer::sum)
.get();

Or without Optional:

Integer reduceSum = Arrays.asList(1, 3, 4, 6, 4)
.stream()
.reduce(0, Integer::sum);