JQuery ——从元素内部选择元素

假设我有一个这样的标记:

<div id="foo">
...
<span id="moo">
...
</span>
...
</div>

我想选择 # 哞。

为什么 $('#foo').find('span')能用，而 $('span', $('#foo'));不能？

311473 次浏览
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both seem to be working.

see fiddle: http://jsfiddle.net/maniator/PSxkS/

小开

Actually, $('#id', this); would select #id at any descendant level, not just the immediate child. Try this instead:

$(this).children('#id');

or

$("#foo > #moo")

or

$("#foo > span")
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Why not just use:

$("#foo span")

or

$("#foo > span")

$('span', $('#foo')); works fine on my machine ;)

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最佳答案

You can use any one these [starting from the fastest]

$("#moo") > $("#foo #moo") > $("div#foo span#moo") > $("#foo span") > $("#foo > #moo")

Take a look

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Have a look here -- to query a sub-element of an element:

$(document.getElementById('parentid')).find('div#' + divID + ' span.child');

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You can use find option to select an element inside another. For example, to find an element with id txtName in a particular div, you can use like

var name = $('#div1').find('#txtName').val();
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....but $('span', $('#foo')); doesn't work?

This method is called as providing selector context.

In this you provide a second argument to the jQuery selector. It can be any css object string just like you would pass for direct selecting or a jQuery element.

eg.

$("span",".cont1").css("background", '#F00');

The above line will select all spans within the container having the class named cont1.

DEMO


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