long startTime = System.currentTimeMillis();
// .. do stuff ..
long elapsed = System.currentTimeMillis()-startTime;
if (elapsed>timeout)
throw new RuntimeException("tiomeout");
如果代码本身不能检查超时,则可以在另一个线程上执行代码,并等待完成或超时。
Callable<ResultType> run = new Callable<ResultType>()
{
@Override
public ResultType call() throws Exception
{
// your code to be timed
}
};
RunnableFuture<ResultType> future = new FutureTask<>(run);
ExecutorService service = Executors.newSingleThreadExecutor();
service.execute(future);
ResultType result = null;
try
{
result = future.get(1, TimeUnit.SECONDS); // wait 1 second
}
catch (TimeoutException ex)
{
// timed out. Try to stop the code if possible.
future.cancel(true);
}
service.shutdown();
}
final Runnable stuffToDo = new Thread() {
@Override
public void run() {
/* Do stuff here. */
}
};
final ExecutorService executor = Executors.newSingleThreadExecutor();
final Future future = executor.submit(stuffToDo);
executor.shutdown(); // This does not cancel the already-scheduled task.
try {
future.get(5, TimeUnit.MINUTES);
}
catch (InterruptedException ie) {
/* Handle the interruption. Or ignore it. */
}
catch (ExecutionException ee) {
/* Handle the error. Or ignore it. */
}
catch (TimeoutException te) {
/* Handle the timeout. Or ignore it. */
}
if (!executor.isTerminated())
executor.shutdownNow(); // If you want to stop the code that hasn't finished.
I compiled some of the other answers into a single utility method:
public class TimeLimitedCodeBlock {
public static void runWithTimeout(final Runnable runnable, long timeout, TimeUnit timeUnit) throws Exception {
runWithTimeout(new Callable<Object>() {
@Override
public Object call() throws Exception {
runnable.run();
return null;
}
}, timeout, timeUnit);
}
public static <T> T runWithTimeout(Callable<T> callable, long timeout, TimeUnit timeUnit) throws Exception {
final ExecutorService executor = Executors.newSingleThreadExecutor();
final Future<T> future = executor.submit(callable);
executor.shutdown(); // This does not cancel the already-scheduled task.
try {
return future.get(timeout, timeUnit);
}
catch (TimeoutException e) {
//remove this if you do not want to cancel the job in progress
//or set the argument to 'false' if you do not want to interrupt the thread
future.cancel(true);
throw e;
}
catch (ExecutionException e) {
//unwrap the root cause
Throwable t = e.getCause();
if (t instanceof Error) {
throw (Error) t;
} else if (t instanceof Exception) {
throw (Exception) t;
} else {
throw new IllegalStateException(t);
}
}
}
}
public class TimeoutBlock {
private final long timeoutMilliSeconds;
private long timeoutInteval=100;
public TimeoutBlock(long timeoutMilliSeconds){
this.timeoutMilliSeconds=timeoutMilliSeconds;
}
public void addBlock(Runnable runnable) throws Throwable{
long collectIntervals=0;
Thread timeoutWorker=new Thread(runnable);
timeoutWorker.start();
do{
if(collectIntervals>=this.timeoutMilliSeconds){
timeoutWorker.stop();
throw new Exception("<<<<<<<<<<****>>>>>>>>>>> Timeout Block Execution Time Exceeded In "+timeoutMilliSeconds+" Milli Seconds. Thread Block Terminated.");
}
collectIntervals+=timeoutInteval;
Thread.sleep(timeoutInteval);
}while(timeoutWorker.isAlive());
System.out.println("<<<<<<<<<<####>>>>>>>>>>> Timeout Block Executed Within "+collectIntervals+" Milli Seconds.");
}
/**
* @return the timeoutInteval
*/
public long getTimeoutInteval() {
return timeoutInteval;
}
/**
* @param timeoutInteval the timeoutInteval to set
*/
public void setTimeoutInteval(long timeoutInteval) {
this.timeoutInteval = timeoutInteval;
}
}
例如:
try {
TimeoutBlock timeoutBlock = new TimeoutBlock(10 * 60 * 1000);//set timeout in milliseconds
Runnable block=new Runnable() {
@Override
public void run() {
//TO DO write block of code to execute
}
};
timeoutBlock.addBlock(block);// execute the runnable block
} catch (Throwable e) {
//catch the exception here . Which is block didn't execute within the time limit
}
例如-在我的例子中,我的请求到达 SQS,当消息被推送时,我的代码逻辑遇到了指定的超时。现在,实际上我的消息被推送到 Queue 中,但是我的主线程认为它由于 TIMEOUT 异常而失败。
This is a type of problem which can be avoided rather than being solved. Like in my case I avoided it by providing a timeout which would suffice in nearly all of the cases.