没有披露指示符的 SwiftUI 导航按钮?

当创建一个包含一行的 List 时,SwiftUI 会自动添加一个公开指示符“ >”?如果我不想要的话,我怎么把它取出来?

    NavigationView {
List {
NavigationButton(destination: DetailView()) {
ListItem()
}
}
.navigationBarTitle(Text("Some title"))
}

在 UITableViewCell 中,您将 Accessory 设置为 Nothing,但是如何在 SwiftUI 中实现这一点呢?

32921 次浏览

As workaround I can suggest to add .padding modifier like this:

NavigationView {
List {
NavigationButton(destination: DetailView()) {
ListItem()
}
}
.navigationBarTitle(Text("Some title"))
}
.padding(.trailing, -32.0)

So you will get rows without visible disclosure:

Result

there is no documentation yet, so you can use ScrollView for now

  NavigationView {
ScrollView {
ForEach(0...100){ x in
NavigationButton(destination: Text("ss")) {
HStack {
Text(String(x))
Spacer()
}
.padding()
.background(Color.white)
.shadow(radius:1,y:1)
}
}
.frame(width: UIScreen.main.bounds.width - 32)
.padding()
}
}

enter image description here

This helps to push and pass the model to the next navigation view controller.

struct ContentView : View {
@State var model = PostListViewModel()


var body: some View {
NavigationView {
List(model.post) { post in
ListCell(listData: post)
}.navigationBarTitle(Text("My Post"))
}
}


}


struct ListCell: View {
var listData: Post
var body: some View {
return NavigationButton(destination: DetailContentView(post: listData)) {
HStack {
ImageRow(model: listData) // Get image
VStack(alignment: .leading) {
Text(listData.login).font(.headline).lineLimit(nil)
Text(listData.url).font(.subheadline).lineLimit(nil)
}.padding(.leading, 10)
}.padding(.init(top: 5, leading: 0, bottom: 5, trailing: 0))
}
}
}

NavigationLink is what we should define in a scope enclosed inside a NavigationView. But when we use NavigationLink it is attached to the enclosing view, so to reuse the same NavigationLink with other views, we use tag which differentiates between different Destinations.

struct SwiftUIView: View {
@State private var viewState: Int? = 0


var body: some View {


NavigationView {
VStack {
NavigationLink(destination: Text("View 1"), tag: 1, selection: $viewState) {
EmptyView()
}


NavigationLink(destination: Text("View 2"), tag: 2, selection: $viewState) {
EmptyView()
}


Text("First View")
.onTapGesture {
self.viewState = 1
}


Text("Second View")
.onTapGesture {
self.viewState = 2
}
}
}
}
}

Here we bind a Hashable property with all the NavigationLinks present in our VStack so that when a particular View is tapped we can notify which Destination should be opened by setting the value of Bindable property. If we don't notify the correct Destination by setting the value of tag, always the View defined inside the Closure of NavigationLink will be clickable and nothing else.

Using this approach you don't need to wrap all your clickable views inside NavigationView, any action on any view can use any NavigationLink just by setting the tag.

Thanks, hope this helps.

As of beta 6, this works well:

struct SwiftUIView: View {
var body: some View {


NavigationView {
List {
HStack {
Text("My Cell Content")
NavigationLink(destination: Text("destination"), label: {
EmptyView()
})
}
}
}
}
}

just came here looking for the answer to this question, but none of the proposed solutions worked for me (can't have an empty view, because i want to put something in the list row; i'm already messing with the padding (and increasing trailing padding didn't seem to work) ... i was about to give up, and then something occurred to me: what if you crank up the z-index of the list row itself? seemed somewhat unlikely, but i gave it a try and, i'll be damned, it worked! i was so pleasantly surprised, i felt like sharing ...

e.g.:

// in body of your list row view
HStack(alignment: .top, spacing: 0.0) {
// stuff ...
}
.zIndex(9999999999)

Swift 5, Xcode 11. ZStack works perfect.

var body: some View {
NavigationView {
List {
ForEach(viewModel.currenciesViewModel) { cellViewModel in
ZStack {
cellViewModel.makeView()
NavigationLink(destination: ChooseCurrencyListView()) {
EmptyView()
}
.buttonStyle(PlainButtonStyle())
}
}
}
.navigationBarHidden(true)
.navigationBarTitle("", displayMode: .inline)
}
}

Setting the NavigationLink width and hiding it did the trick for me

List {
ForEach(pages) { page in
HStack(spacing: 0) {
Text("Something")


NavigationLink(destination: Text("Somewhere")) {
EmptyView()
}
.frame(width: 0)
.opacity(0)
}
}
}

Removing List and just using ForEach works fine with navigation link. You just have to create your own list row. This works for me

NavigationView {
ForEach(pages) {
page in
NavigationLink(destination: DetailView()) {
ListItem()
}
}
}

You don't have to use NavigationLink to wrap your Label directly. It will work as long as the link is anywhere in your view hierarchy.

Here I've wrapped it in a button, which allows you to trigger an action prior to pushing the view. Since the NavigationLink has an EmptyView for the label the disclosure indicator is not visible. You can also style this with ButtonStyle.

struct NavigationButton<Destination: View, Label: View>: View {
var action: () -> Void = { }
var destination: () -> Destination
var label: () -> Label


@State private var isActive: Bool = false


var body: some View {
Button(action: {
self.action()
self.isActive.toggle()
}) {
self.label()
.background(NavigationLink(destination: self.destination(), isActive: self.$isActive) {
EmptyView()
})
}
}
}

And to use it:

NavigationButton(
action: { print("tapped!") },
destination: { Text("Pushed View") },
label: { Text("Tap me") }
)

The easiest one. The content for each item in the list.

ZStack {
NavigationLink(destination: DetailView()) {
EmptyView()
}.hidden()
RowView()
}

Works well for me!

import SwiftUI


struct LandmarkList: View {
var body: some View {
NavigationView {
List(landmarkData) { landmark in
LandmarkRow(landmark: landmark)
NavigationLink(destination: LandmarkDetail(landmark: landmark)) {
EmptyView()
}
}
.navigationBarTitle(Text("Landmarks"))
}
}
}


struct LandmarkList_Previews: PreviewProvider {
static var previews: some View {
ForEach(["iPhone SE", "iPhone 11 Pro Max"], id: \.self) { deviceName in
LandmarkList()
.previewDevice(PreviewDevice(rawValue: deviceName))
.previewDisplayName(deviceName)
}
}
}


enter image description here

What you can do, if you are using list, is setting the navigationlink to hidden and its frame width to zero.

    HStack{
Button(action: {self.statusShow = 1}, label: {
Image(systemName: "info.circle")
})
NavigationLink(destination: StimulatorSettingView(),
tag: 1,
selection: self.$statusShow){
EmptyView()


}.hidden().frame(width: 0)
}

This worked for me.

Once you put your button in a scrollview, the disclosure button will be hidden. Just make sure to disable your scroll indicator.

You can also put it in the .background modifier:

List {
Text("Go to...")
.background(NavigationLink("", destination: Text("Detail View")))
}

If you already have the background modifier on the Text, you can wrap the Text in a HStack and apply background to the HStack.

Use .frame(width: 0).opacity(0.0):

NavigationView {
List {
ForEach(options) {
option in
ZStack {
YourView(option: option)
NavigationLink(destination: ProductListView(),
label: {
EmptyView()
}).frame(width: 0).opacity(0.0)
}.listRowInsets(EdgeInsets())
}
}.navigationBarHidden(true)
}

If you need children behaviour for List and NavigationLink, without additional discloser in the same time, I want to promote this tricky solution, main point at HStack

var body: some View {
NavigationView {
List(items, children: \.items) { item in
ZStack {
NavigationLink(destination: DetailsView()) {
EmptyView()
}.hidden()
HStack {
RowView(item: item)
Spacer()
}
}
}
}
}

My version of this solution is to make a view modifier. I think it's the cleanest way, as it doesn't use AnyView.

Note that this solution runs the init() for the destination when it draws the element the .navigationLink() is attached to.

Usage

Text("Link")
.navigationLink({
// put your destination here
})


How To

import SwiftUI


extension View {
func navigationLink<Destination: View>(_ destination: @escaping () -> Destination) -> some View {
modifier(NavigationLinkModifier(destination: destination))
}
}


fileprivate struct NavigationLinkModifier<Destination: View>: ViewModifier {


@ViewBuilder var destination: () -> Destination


func body(content: Content) -> some View {
content
.background(
NavigationLink(destination: self.destination) { EmptyView() }.opacity(0)
)
}
}

Here's a reusable "plain" navigation link view (i.e. without the chevron disclosure indicator) that can be a drop-in replacement for NavigationLink:

struct PlainNavigationLink<Label, Destination>: View where Label: View, Destination: View {
@ViewBuilder var destination: () -> Destination
@ViewBuilder var label: () -> Label


var body: some View {
label()
.background(
NavigationLink(destination: destination, label: {})
.opacity(0)
)
}
}

To use it, simply replace NavigationLink with PlainNavigationLink:

NavigationView { // or NavigationStack in iOS 16
List {
ForEach(1...30, id: \.self) { _ in
PlainNavigationLink {
Text("Hello, world!")
} label: {
Text("Hello, world!")
}
}
}
}

We can also extend it with convenience initializers for LocalizedStringKey and String, just like NavigationLink does.