将字符串中的空格转换为% 20？

如何将字符串中的空格转换为 %20？

下面是我的尝试:

$str = "What happens here?";
echo urlencode($str);

输出为 "What+happens+here%3F"，因此空格不表示为 %20。

我做错了什么？

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The plus sign is the historic encoding for a space character in URL parameters, as documented in the help for the urlencode() function.

That same page contains the answer you need - use rawurlencode() instead to get RFC 3986 compatible encoding.

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最佳答案

Use the rawurlencode function instead.

小开

I believe that, if you need to use the %20 variant, you could perhaps use rawurlencode().