如何在 Oracle 中插入时间戳？

我有一个 Oracle 数据库，其中有一个 timestamp字段。在此字段中插入 timestamp的正确 SQL 代码是什么？

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INSERT
INTO    mytable (timestamp_field)
VALUES  (CURRENT_TIMESTAMP)

CURRENT_TIMESTAMP and SYSTIMESTAMP are Oracle reserved words for this purpose. They are the timestamp analog of SYSDATE.

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最佳答案 
insert
into tablename (timestamp_value)
values (TO_TIMESTAMP(:ts_val, 'YYYY-MM-DD HH24:MI:SS'));

if you want the current time stamp to be inserted then:

insert
into tablename (timestamp_value)
values (CURRENT_TIMESTAMP);
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Kind of depends on where the value you want to insert is coming from. If you want to insert the current time you can use CURRENT_TIMESTAMP as shown in other answers (or SYSTIMESTAMP).

If you have a time as a string and want to convert it to a timestamp, use an expression like

to_timestamp(:timestamp_as_string,'MM/DD/YYYY HH24:MI:SS.FF3')

The time format components are, I hope, self-explanatory, except that FF3 means 3 digits of sub-second precision. You can go as high as 6 digits of precision.

If you are inserting from an application, the best answer may depend on how the date/time value is stored in your language. For instance you can map certain Java objects directly to a TIMESTAMP column, but you need to understand the JDBC type mappings.

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First of all you need to make the field Nullable, then after that so simple - instead of putting a value put this code CURRENT_TIMESTAMP.

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INSERT INTO TABLE_NAME (TIMESTAMP_VALUE) VALUES (TO_TIMESTAMP('2014-07-02 06:14:00.742000000', 'YYYY-MM-DD HH24:MI:SS.FF'));
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CREATE TABLE Table1 (
id int identity(1, 1) NOT NULL,
Somecolmn varchar (5),
LastChanged [timestamp] NOT NULL)

this works for mssql 2012

INSERT INTO Table1 VALUES('hello',DEFAULT)
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Inserting date in sql

insert
into tablename (timestamp_value)
values ('dd-mm-yyyy hh-mm-ss AM');

If suppose we wanted to insert system date

insert
into tablename (timestamp_value)
values (sysdate);
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For my own future reference:

With cx_Oracle use cursor.setinputsize(...):

mycursor = connection.cursor();


mycursor.setinputsize( mytimestamp=cx_Oracle.TIMESTAMP );
params = { 'mytimestamp': timestampVar };
cusrsor.execute("INSERT INTO mytable (timestamp_field9 VALUES(:mytimestamp)", params);

No converting in the db needed. See Oracle Documentation

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I prefer ANSI timestamp literals:

insert into the_table
(the_timestamp_column)
values
(timestamp '2017-10-12 21:22:23');

More details in the manual: https://docs.oracle.com/database/121/SQLRF/sql_elements003.htm#SQLRF51062

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One can simply use

INSERT INTO MY_TABLE(MY_TIMESTAMP_FIELD)
VALUES (TIMESTAMP '2019-02-15 13:22:11.871+02:00');

This way you won't have to worry about date format string, just use default timestamp format.

Works with Oracle 11, have no idea if it does for earlier Oracle versions.

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The below sample working fine for me.

INSERT INTO "DB"."TBL" (UPDATEDDATETIME)
VALUES (TO_TIMESTAMP('2022-07-12 17:16:05.551000000', 'YYYY-MM-DD HH24:MI:SS.FF'))

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