If you are looking for the size of Fixnum objects (integers small enough to store in a single machine word), you can call 0.size to get the number of bytes. I would guess it should be 4 on 32-bit builds, but I can't test that right now. Also, the largest Fixnum is apparently 2**30 - 1 (or 2**62 - 1), because one bit is used to mark it as an integer instead of an object reference.
Reading the friendly manual? Who'd want to do that?
start = Time.now
largest_known_fixnum = 1
smallest_known_bignum = nil
until smallest_known_bignum == largest_known_fixnum + 1
if smallest_known_bignum.nil?
next_number_to_try = largest_known_fixnum * 1000
else
next_number_to_try = (smallest_known_bignum + largest_known_fixnum) / 2 # Geometric mean would be more efficient, but more risky
end
if next_number_to_try <= largest_known_fixnum ||
smallest_known_bignum && next_number_to_try >= smallest_known_bignum
raise "Can't happen case"
end
case next_number_to_try
when Bignum then smallest_known_bignum = next_number_to_try
when Fixnum then largest_known_fixnum = next_number_to_try
else raise "Can't happen case"
end
end
finish = Time.now
puts "The largest fixnum is #{largest_known_fixnum}"
puts "The smallest bignum is #{smallest_known_bignum}"
puts "Calculation took #{finish - start} seconds"