我怎样才能完全禁用调用声明() ？

我的代码充满了对 assert(condition)的调用。在调试版本中，我使用 g++ -g触发我的断言。出乎意料的是，同样的断言在我的版本中也会被触发，这个版本没有使用 -g选项进行编译。

如何在编译时完全禁用断言？我是否应该在我生成的任何构建中明确定义 NDEBUG，而不管它们是调试、发布还是其他任何东西？

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最佳答案

You must #define NDEBUG (or use the flag -DNDEBUG with g++) this will disable assert as long as it's defined before the inclusion of the assert header file.

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You can either disable assertions completely by

#define NDEBUG
#include <assert.h>

or you can set NDEBUG (via -DNDEBUG) in your makefile/build procedure depending on whether you want a productive or dev version.

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Yes, define NDEBUG on the command line/build system with the preprocessor/compiler option -DNDEBUG.

This has nothing to do with the debugging info inserted by -g.

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The -g flag doesn't affect the operation of assert, it just ensures that various debugging symbols are available.

Setting NDEBUG is the standard (as in official, ISO standard) way of disabling assertions.

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Use #define NDEBUG

7.2 Diagnostics

1 The header deﬁnes the assert macro and refers to another macro,

NDEBUG

which is not deﬁned by <assert.h>. If NDEBUG is deﬁned as a macro name at the point in the source ﬁle where is included, the assert macro is deﬁned simply as

#define assert(ignore) ((void)0)

The assert macro is redeﬁned according to the current state of NDEBUG each time that <assert.h> is included.