如何在 C + + 中打印字符串

我试过了，但没用。

#include <string>
string someString("This is a string.");
printf("%s\n", someString);

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小开

You need to access the underlying buffer:

printf("%s\n", someString.c_str());

Or better use cout << someString << endl; (you need to #include <iostream> to use cout)

Additionally you might want to import the std namespace using using namespace std; or prefix both string and cout with std::.

小开

最佳答案

#include <iostream>
std::cout << someString << "\n";

printf("%s\n",someString.c_str());

小开

If you'd like to use printf(), you might want to also:

#include <stdio.h>

小开

You can't call "printf" with a std::string in parameter. The "%s" is designed for C-style string : char* or char []. In C++ you can do like that :

#include <iostream>
std::cout << YourString << std::endl;

If you absolutely want to use printf, you can use the "c_str()" method that give a char* representation of your string.

printf("%s\n",YourString.c_str())

小开

You need #include<string> to use string AND #include<iostream> to use cin and cout. (I didn't get it when I read the answers). Here's some code which works:

#include<string>
#include<iostream>
using namespace std;


int main()
{
string name;
cin >> name;
string message("hi");
cout << name << message;
return 0;
}

小开

While using string, the best possible way to print your message is:

#include <iostream>
#include <string>
using namespace std;


int main(){
string newInput;
getline(cin, newInput);
cout<<newInput;
return 0;
}

this can simply do the work instead of doing the method you adopted.