如何使用“ find”按正则表达式搜索文件名

我试图找到所有的文件日期和所有的文件3天以前或更多。

find /home/test -name 'test.log.\d{4}-d{2}-d{2}.zip' -mtime 3

它没有列出任何东西，有什么问题吗？

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小开
最佳答案 
find /home/test -regextype posix-extended -regex '^.*test\.log\.[0-9]{4}-[0-9]{2}-[0-9]{2}\.zip' -mtime +3
  1. -name uses globular expressions, aka wildcards. What you want is -regex
  2. To use intervals as you intend, you need to tell find to use Extended Regular Expressions via the -regextype posix-extended flag
  3. You need to escape out the periods because in regex a period has the special meaning of any single character. What you want is a literal period denoted by \.
  4. To match only those files that are greater than 3 days old, you need to prefix your number with a + as in -mtime +3.

Proof of Concept

$ find . -regextype posix-extended -regex '^.*test\.log\.[0-9]{4}-[0-9]{2}-[0-9]{2}\.zip'
./test.log.1234-12-12.zip
小开

Use -regex not -name, and be aware that the regex matches against what find would print, e.g. "/home/test/test.log" not "test.log"

小开

Use -regex:

From the man page:

-regex pattern
File name matches regular expression pattern.  This is a match on the whole path, not a search.  For example, to match a file named './fubar3',  you  can  use  the
regular expression '.*bar.' or '.*b.*3', but not 'b.*r3'.

Also, I don't believe find supports regex extensions such as \d. You need to use [0-9].

find . -regex '.*test\.log\.[0-9][0-9][0-9][0-9]-[0-9][0-9]-[0-9][0-9]\.zip'
小开

Start with:

find . -name '*.log.*.zip' -a -mtime +1

You may not need a regex, try:

 find . -name '*.log.*-*-*.zip' -a -mtime +1

You will want the +1 in order to match 1, 2, 3 ...

小开

Just little elaboration of regex for search a directory and file

Find a directroy with name like book

find . -name "*book*" -type d

Find a file with name like book word

find . -name "*book*" -type f

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