使用标记拆分 C + + std: : 字符串，例如“ ;

You could use a string stream and read the elements into the vector.

Here are many different examples...

A copy of one of the examples:

std::vector<std::string> split(const std::string& s, char seperator)
{
std::vector<std::string> output;


std::string::size_type prev_pos = 0, pos = 0;


while((pos = s.find(seperator, pos)) != std::string::npos)
{
std::string substring( s.substr(prev_pos, pos-prev_pos) );


output.push_back(substring);


prev_pos = ++pos;
}


output.push_back(s.substr(prev_pos, pos-prev_pos)); // Last word


return output;
}

I find std::getline() is often the simplest. The optional delimiter parameter means it's not just for reading "lines":

#include <sstream>
#include <iostream>
#include <vector>


using namespace std;


int main() {
vector<string> strings;
istringstream f("denmark;sweden;india;us");
string s;
while (getline(f, s, ';')) {
cout << s << endl;
strings.push_back(s);
}
}

There are several libraries available solving this problem, but the simplest is probably to use Boost Tokenizer:

#include <iostream>
#include <string>
#include <boost/tokenizer.hpp>
#include <boost/foreach.hpp>


typedef boost::tokenizer<boost::char_separator<char> > tokenizer;


std::string str("denmark;sweden;india;us");
boost::char_separator<char> sep(";");
tokenizer tokens(str, sep);


BOOST_FOREACH(std::string const& token, tokens)
{
std::cout << "<" << *tok_iter << "> " << "\n";
}