如何使用 gson 库将字符串转换为 JsonObject

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You don't need to use JsonObject. You should be using Gson to convert to/from JSON strings and your own Java objects.

(Serialization)

Gson gson = new Gson();
gson.toJson(1);                   // prints 1
gson.toJson("abcd");              // prints "abcd"
gson.toJson(new Long(10));        // prints 10
int[] values = { 1 };
gson.toJson(values);              // prints [1]

(Deserialization)

int one = gson.fromJson("1", int.class);
Integer one = gson.fromJson("1", Integer.class);
Long one = gson.fromJson("1", Long.class);
Boolean false = gson.fromJson("false", Boolean.class);
String str = gson.fromJson("\"abc\"", String.class);
String anotherStr = gson.fromJson("[\"abc\"]", String.class)

小开

Looks like the above answer did not answer the question completely.

I think you are looking for something like below:

class TransactionResponse {


String Success, Message;
List<Response> Response;


}


TransactionResponse = new Gson().fromJson(response, TransactionResponse.class);

where my response is something like this:

{"Success":false,"Message":"Invalid access token.","Response":null}

As you can see, the variable name should be same as the Json string representation of the key in the key value pair. This will automatically convert your gson string to JsonObject.

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最佳答案

You can convert it to a JavaBean if you want using:

 Gson gson = new GsonBuilder().setPrettyPrinting().create();
gson.fromJson(jsonString, JavaBean.class)

To use JsonObject, which is more flexible, use the following:

String json = "{\"Success\":true,\"Message\":\"Invalid access token.\"}";
JsonParser jsonParser = new JsonParser();
JsonObject jo = (JsonObject)jsonParser.parse(json);
Assert.assertNotNull(jo);
Assert.assertTrue(jo.get("Success").getAsString());

Which is equivalent to the following:

JsonElement jelem = gson.fromJson(json, JsonElement.class);
JsonObject jobj = jelem.getAsJsonObject();

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To do it in a simpler way, consider below:

JsonObject jsonObject = (new JsonParser()).parse(json).getAsJsonObject();

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JsonObject jsonObject = (JsonObject) new JsonParser().parse("YourJsonString");

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String string = "abcde"; // The String which Need To Be Converted
JsonObject convertedObject = new Gson().fromJson(string, JsonObject.class);

I do this, and it worked.

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Gson gson = new Gson();
YourClass yourClassObject = new YourClass();
String jsonString = gson.toJson(yourClassObject);

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String emailData = {"to": "abc@abctest.com","subject":"User details","body": "The user has completed his training"
}


// Java model class
public class EmailData {
public String to;
public String subject;
public String body;
}


//Final Data
Gson gson = new Gson();
EmailData emaildata = gson.fromJson(emailData, EmailData.class);

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Note that as of Gson 2.8.6, instance method JsonParser.parse has been deprecated and replaced by static method JsonParser.parseString:

JsonObject jsonObject = JsonParser.parseString(json).getAsJsonObject();

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if you just want to convert string to json then use:

use org.json: https://mvnrepository.com/artifact/org.json/json/20210307

<!-- https://mvnrepository.com/artifact/org.json/json -->
<dependency>
<groupId>org.json</groupId>
<artifactId>json</artifactId>
<version>20210307</version>
</dependency>

import these

import org.json.JSONException;
import org.json.JSONObject;
import org.json.JSONArray;

Now convert it as

//now you can convert string to array and object without having complicated maps and objects
 

try {
JSONArray jsonArray = new JSONArray("[1,2,3,4,5]");
//you can give entire jsonObject here
JSONObject jsonObject= new JSONObject("{\"name\":\"test\"}") ;
System.out.println("outputarray: "+ jsonArray.toString(2));
System.out.println("outputObject: "+ jsonObject.toString(2));
}catch (JSONException err){
System.out.println("Error: "+ err.toString());
}

小开

You can use the already Gson existing method :

inline fun <I, reified O> I.convert():O {
val json = gson.toJson(this)
return gson.fromJson(json, object : TypeToken<O>() {}.type)
}