如何将一个数提高到一个幂？

Rust provides exponentiation via methods pow and checked_pow. The latter guards against overflows. Thus, to raise 2 to the power of 10, do:

let base: i32 = 2; // an explicit type is required
assert_eq!(base.pow(10), 1024);

The caret operator ^ is not used for exponentiation, it's the bitwise XOR operator.

Here is the simplest method which you can use:

let a = 2; // Can also explicitly define type i.e. i32
let a = i32::pow(a, 10);

It will output "2 raised to the power of 10", i.e.:

1024

For integers:

fn main() {
let n = u32::pow(2, 10);
println!("{}", n == 1024);
}

For floats:

fn main() {
// example 1
let f = f32::powf(2.0, 10.0);
// example 2
let g = f32::powi(2.0, 10);
// print
println!("{}", f == 1024.0 && g == 1024.0);
}

or, since your base is 2, you can also use shift:

fn main() {
let n = 2 << 9;
println!("{}", n == 1024);
}

• https://doc.rust-lang.org/std/primitive.f32.html#method.powf
• https://doc.rust-lang.org/std/primitive.f32.html#method.powi
• https://doc.rust-lang.org/std/primitive.u32.html#method.pow

I was trying the same thing as the OP. Thanks to the other answer authors.

Here's a variation that works for me:

let n = 2u32.pow(10);

This uses a literal unsigned 32 bit integer to set the type and base, then calls the pow() function on it.

Bit shifting is a good way to do this particular case:

assert_eq!(1 << 10, 1024);