如何从一个目录递归查找所有文件扩展名？

我可以使用什么命令或命令集来返回目录(包括子目录)中的所有文件扩展名？

现在，我正在使用 ls和 grep的不同组合，但是我找不到任何可伸缩的解决方案。

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最佳答案

How about this: 

find . -type f -name '*.*' | sed 's|.*\.||' | sort -u
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if you are using Bash 4+

shopt -s globstar
for file in **/*.*
do
echo "${file##*.}
done

Ruby(1.9+)

ruby -e 'Dir["**/*.*"].each{|x|puts x.split(".")[-1]}' | sort -u
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Yet another solution using find (that should even sort file extensions with embedded newlines correctly):

# [^.]: exclude dotfiles
find . -type f -name "[^.]*.*" -exec bash -c '
printf "%s\000" "${@##*.}"
' argv0 '{}' + |
sort -uz |
tr '\0' '\n'
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find . -type f | sed 's|.*\.||' | sort -u

Also works on mac.

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Boooom another:

find * | awk -F . {'print $2'} | sort -u
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ls -1 | sed 's/.*\.//' | sort -u

Update: You are correct Matthew. Based on your comment, here is an updated version:

ls -R1 | egrep -C 0 "[^\.]+\.[^\./:]+$" | sed 's/.*\.//' | sort -u

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I was just quickly trying this as I was searching Google for a good answer. I am more Regex inclined than Bash, but this also works for subdirectories. I don't think includes files without extensions either:

ls -R | egrep '(\.\w+)$' -o | sort | uniq -c | sort -r

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list all extensions and their counts of current and all sub-directories

ls -1R | sed 's/[^\.]*//' | sed 's/.*\.//' | sort | uniq -c
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Another one, similar to others but only uses two programs (find and awk)

find ./ -type f -name "*\.*" -printf "%f\n" | awk -F . '!seen[$NF]++ {print $NF}'

-type f restricts it to just files, not directories

-name "*\.*" ensures the filename has a . in it.

-printf "%f\n" prints just the filename, not the path to the filename.

-F . makes awk utilize a period as the field separator.

$NF is the last field, separated by periods.

!seen[$NF]++ evaluates to true the first time an extension is encountered, and false every other time it is encountered.

print $NF prints the extension.


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