只从此元素中提取文本，而不从其子元素中提取文本

我只想提取汤中最上面的元素的文本; 然而 soup.text 也提供了所有子元素的文本:

是的

import BeautifulSoup
soup=BeautifulSoup.BeautifulSoup('<html>yes<b>no</b></html>')
print soup.text

输出是 yesno，我只需要“ yes”。

实现这一目标的最佳方法是什么？

编辑 : 我还希望在解析‘ <html><b>no</b>yes</html>’时输出 yes。

76563 次浏览

小开

You could use contents

>>> print soup.html.contents[0]
yes

or to get all the texts under html, use findAll(text=True, recursive=False)

>>> soup = BeautifulSoup.BeautifulSOAP('<html>x<b>no</b>yes</html>')
>>> soup.html.findAll(text=True, recursive=False)
[u'x', u'yes']

above joined to form a single string

>>> ''.join(soup.html.findAll(text=True, recursive=False))
u'xyes'

小开

最佳答案

what about .find(text=True)?

>>> BeautifulSoup.BeautifulSOAP('<html>yes<b>no</b></html>').find(text=True)
u'yes'
>>> BeautifulSoup.BeautifulSOAP('<html><b>no</b>yes</html>').find(text=True)
u'no'

EDIT:

I think that I've understood what you want now. Try this:

>>> BeautifulSoup.BeautifulSOAP('<html><b>no</b>yes</html>').html.find(text=True, recursive=False)
u'yes'
>>> BeautifulSoup.BeautifulSOAP('<html>yes<b>no</b></html>').html.find(text=True, recursive=False)
u'yes'

小开

You might want to look into lxml's soupparser module, which has support for XPath:

>>> from lxml.html.soupparser import fromstring
>>> s1 = '<html>yes<b>no</b></html>'
>>> s2 = '<html><b>no</b>yes</html>'
>>> soup1 = fromstring(s1)
>>> soup2 = fromstring(s2)
>>> soup1.xpath("text()")
['yes']
>>> soup2.xpath("text()")
['yes']

小开

This works for me in bs4:

import bs4
node = bs4.BeautifulSoup('<html><div>A<span>B</span>C</div></html>').find('div')
print "".join([t for t in node.contents if type(t)==bs4.element.NavigableString])

output:

AC