有没有一种检测目录/file/symlink/etc 实体(更通用的)是否存在的方法?
我需要一个单一的函数,因为我需要检查一个路径数组,可能是目录,文件或符号链接。我知道 File.exists?"file_path"适用于目录和文件,但不适用于符号链接(即 File.symlink?"symlink_path")。
File.exists?"file_path"
File.symlink?"symlink_path"
Why not define your own function File.exists?(path) or File.symlink?(path) and use that?
File.exists?(path) or File.symlink?(path)
The standard File module has the usual file tests available:
RUBY_VERSION # => "1.9.2" bashrc = ENV['HOME'] + '/.bashrc' File.exist?(bashrc) # => true File.file?(bashrc) # => true File.directory?(bashrc) # => false
You should be able to find what you want there.
OP: "Thanks but I need all three true or false"
Obviously not. Ok, try something like:
def file_dir_or_symlink_exists?(path_to_file) File.exist?(path_to_file) || File.symlink?(path_to_file) end file_dir_or_symlink_exists?(bashrc) # => true file_dir_or_symlink_exists?('/Users') # => true file_dir_or_symlink_exists?('/usr/bin/ruby') # => true file_dir_or_symlink_exists?('some/bogus/path/to/a/black/hole') # => false
Just File.exist? on it's own will take care of all of the above for you
File.exist?