可编码类不符合协议可解码

Why am I getting a "Type 'Bookmark' does not conform to protocol 'Decodable'" error message

It's either because Publication isn't Decodable (you have not shown what it is, so it's hard to tell) or because of the weak designation on publication.

Either way, it's easy to fix: you just need to implement init(from:) to complete the implementation of Decodable; the compiler is simply telling you that this implementation cannot be synthesized.

The compiler cannot synthesise the required init(from:) method due to the weak reference, so you need to write it yourself.

class Bookmark: Codable {
weak var publication: Publication?
var indexPath: [Int]
var locationInText = 0


private enum CodingKeys: String, CodingKey {
case indexPath
case locationInText
}


init(publication: Publication?, indexPath: [Int]) {
self.publication = publication
self.indexPath = indexPath
}


required init(from decoder:Decoder) throws {
let values = try decoder.container(keyedBy: CodingKeys.self)
indexPath = try values.decode([Int].self, forKey: .indexPath)
locationInText = try values.decode(Int.self, forKey: .locationInText)
}
}

On the hindsight, I received a similar error when trying to set Codable to my class which consisted of NSNumber type variables. See image below:

Changing NSNumber to primitive data type Int resolved the issue. See below:

I'm guessing this might be true for other datatypes that require bridging to Swift Standard Library Value Types such as NSString, NSArray and so on

I had a similar issue which I stumbled upon this fix to. As I am new to Swift, I am unsure as to why it works! If anyone knows I would appreciate the knowledge.

I changed this:

let id, type: Int

to this:

let id: Int
let type: Int

Another reason you could get this message is if your CodingKeys enum isn't exhaustive. If you have three properties in the data type, then your CodingKeys enum needs to have three property/name cases as well.

In-short, while implementing Codable, all properties which are non-primitive data type (mean class type or may it can be objective-c class) must be Codable.

   weak var publication: Publication?

in this case publication is of type class so Publication must have implemented Codable

Simply because your CodingKeys enum is not exhaustive, add publication property to the enum to achieve that.

try this:

class Bookmark: Codable {
weak var publication: Publication?
var indexPath: [Int]
var locationInText = 0


// All your properties should be included
enum CodingKeys: String, CodingKey {
case indexPath
case locationInText
case publication   // this one was missing
}
}

You wont need the init method anymore as the implementation now can be synthesized.

You can omit a property from coding keys enum, only if it has a default value.

From apple docs

Omit properties from the CodingKeys enumeration if they won't be present when decoding instances, or if certain properties shouldn't be included in an encoded representation. A property omitted from CodingKeys needs a default value in order for its containing type to receive automatic conformance to Decodable or Codable.

Bit of a daft one but in case it helps someone else. I got this error because I put enum CodingKeys: CodingKeys instead of enum CodingKeys: CodingKey.

Any class to be a codeable must have it's all property codeable. Standard library types like String, Int, Double and Foundation types like Date, Data, and UR confirm the codeable protocol but some doesn't.

For e.g below Note class have all properties of string which confirm codable protocol so no error:

But UIImage don't confirm codable protocol so it throw error:

In a similar scenario, I was getting the same issue because the variable name in my CodingKeys was not the same as a class variable. See below