How to sort a file, based on its numerical values for a field?

Example file.txt:

  100 foo
2 bar
300 tuu

When using sort -k 1,1 file.txt, the order of lines will not change, though we are expecting :

  2 bar
100 foo
300 tuu

How to sort a field consisting of numbers based on the absolute numerical value?

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Use sort -n or sort --numeric-sort.

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最佳答案

Take a peek at the man page for sort...

   -n, --numeric-sort
compare according to string numerical value

So here is an example...

sort -n filename
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You have to use the numeric sort option:

sort -n -k 1,1 File.txt
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Well, most other answers here refer to

sort -n

However, I'm not sure this works for negative numbers. Here are the results I get with sort version 6.10 on Fedora 9.

Input file:

-0.907928466796875
-0.61614990234375
1.135406494140625
0.48614501953125
-0.4140167236328125

Output:

-0.4140167236328125
0.48614501953125
-0.61614990234375
-0.907928466796875
1.135406494140625

Which is obviously not ordered by numeric value.

Then, I guess that a more precise answer would be to use sort -n but only if all the values are positive.

P.S.: Using sort -g returns just the same results for this example

Edit:

Looks like the locale settings affect how the minus sign affects the order (see here). In order to get proper results I just did:

LC_ALL=C sort -n filename.txt
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    echo " Enter any values to sorting: "
read n
i=0;
t=0;
echo " Enter the n value: "
for(( i=0;i<n;i++ ))
do
read s[$i]
done
for(( i=0;i<n;i++ ))
do
for(( j=i+1;j<n;j++ ))
do
if [ ${s[$i]} -gt ${s[$j]} ]
then
t=${s[$i]}
s[$i]=${s[$j]}
s[$j]=$t
fi
done
done
for(( i=0;i<n;i++ ))
do
echo " ${s[$i]}  "
done
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Use sort -nr for sorting in descending order. Refer

Sort

Refer the above Man page for further reference

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If you are sorting strings that are mixed text & numbers, for example filenames of rolling logs then sorting with sort -n doesn't work as expected:

$ ls |sort -n
output.log.1
output.log.10
output.log.11
output.log.12
output.log.13
output.log.14
output.log.15
output.log.16
output.log.17
output.log.18
output.log.19
output.log.2
output.log.20
output.log.3
output.log.4
output.log.5
output.log.6
output.log.7
output.log.8
output.log.9

In that case option -V does the trick:

$ ls |sort -V
output.log.1
output.log.2
output.log.3
output.log.4
output.log.5
output.log.6
output.log.7
output.log.8
output.log.9
output.log.10
output.log.11
output.log.12
output.log.13
output.log.14
output.log.15
output.log.16
output.log.17
output.log.18
output.log.19
output.log.20

from man page:

   -V, --version-sort
natural sort of (version) numbers within text
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You must do the following command:

sort -n -k1 filename

That should do it :)


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