How to transform Scala collection of Option[X] to collection of X

I'm starting to explore Scala, and one of the things I'm intrigued by is the Option type and the promise of being able to eliminate null related errors.

However I haven't been able to work out how to transform a list (or other collection) of, say, Option[String], to a collection of String (obviously filtering out any values that are None).

In other words, how do I get from this:

List[Option[Int]] = List(Some(1))

... to this:

List[Int] = List(1)

I'm using Scala 2.8 if that has any impact on the answer.

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最佳答案 
val list1 = List(Some(1), None, Some(2))
val list2 = list1.flatten // will be: List(1,2)
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For educational purposes, you might like some alternatives:

scala> val list1 = List(Some(1), None, Some(2))
list1: List[Option[Int]] = List(Some(1), None, Some(2))


scala> list1 flatten
res0: List[Int] = List(1, 2)


// Expanded to show the implicit parameter
scala> list1.flatten(Option.option2Iterable)
res1: List[Int] = List(1, 2)


scala> list1 flatMap (x => x)
res2: List[Int] = List(1, 2)


scala> list1 flatMap Option.option2Iterable
res3: List[Int] = List(1, 2)


// collect is a simultaneous map + filter
scala> list1 collect { case Some(x) => x }
res4: List[Int] = List(1, 2)

With Scalaz, you can perform a slightly different operation called sequence, that returns Option[List[Int]].

scala> import scalaz._; import Scalaz._
import scalaz._
import Scalaz._


scala> val list1: List[Option[Int]] = List(Some(1), None, Some(2))
list1: List[Option[Int]] = List(Some(1), None, Some(2))


scala> list1.sequence
res1: Option[List[Int]] = None


scala> val list2: List[Option[Int]] = List(Some(1), Some(2))
list2: List[Option[Int]] = List(Some(1), Some(2))


scala> list2.sequence
res2: Option[List[Int]] = Some(List(1, 2))

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