如何在颤动中获得唯一的设备 ID？

If you're serving ads you can use ASIdentifierManager. You should only use it for ads. There is no general UDID mechanism provided by the OS on iOS, for privacy reasons.

If you're using firebase_auth plugin you could signInAnonymously and then use the id of the FirebaseUser. This will give you an identifier that is specific to your Firebase app.

There is a plugin called device_info. You can get it here.

Check the official example here

 static Future<List<String>> getDeviceDetails() async {
String deviceName;
String deviceVersion;
String identifier;
final DeviceInfoPlugin deviceInfoPlugin = new DeviceInfoPlugin();
try {
if (Platform.isAndroid) {
var build = await deviceInfoPlugin.androidInfo;
deviceName = build.model;
deviceVersion = build.version.toString();
identifier = build.androidId;  //UUID for Android
} else if (Platform.isIOS) {
var data = await deviceInfoPlugin.iosInfo;
deviceName = data.name;
deviceVersion = data.systemVersion;
identifier = data.identifierForVendor;  //UUID for iOS
}
} on PlatformException {
print('Failed to get platform version');
}


//if (!mounted) return;
return [deviceName, deviceVersion, identifier];
}

You can store this UUID in the Keychain. This way you can set an unique ID for your device.

UPDATE

device_info is now device_info_plus

I just published a plugin to provide a solution to your problem. It uses Settings.Secure.ANDROID_ID for Android and relies on identifierForVendor and the keychain for iOS to make the behaviour equivalent to Android's. Here's the link.

Use device_id plugin

1. Add in your following code in your .yaml file.

   device_id: ^0.1.3
   

2. Add import in your class

   import 'package:device_id/device_id.dart';
   

3. Now get device id from:

   String deviceid = await DeviceId.getID;
   

Null safe code

Use device_info_plus plugin developed by Flutter community. This is how you can get IDs on both platform.

In your pubspec.yaml file add this:

dependencies:
device_info_plus: ^3.2.3

Create a method:

Future<String?> _getId() async {
var deviceInfo = DeviceInfoPlugin();
if (Platform.isIOS) { // import 'dart:io'
var iosDeviceInfo = await deviceInfo.iosInfo;
return iosDeviceInfo.identifierForVendor; // unique ID on iOS
} else if(Platform.isAndroid) {
var androidDeviceInfo = await deviceInfo.androidInfo;
return androidDeviceInfo.androidId; // unique ID on Android
}
}

Usage:

String? deviceId = await _getId();

Update 1/3/2021: The recommended way is now the extended community plugin called device_info_plus. It supports more platforms than device_info and aims to support all that are supported by flutter. Here is an example usage:

import 'package:flutter/foundation.dart' show kIsWeb;
import 'package:device_info_plus/device_info_plus.dart';
import 'dart:io';


Future<String> getDeviceIdentifier() async {
String deviceIdentifier = "unknown";
DeviceInfoPlugin deviceInfo = DeviceInfoPlugin();


if (Platform.isAndroid) {
AndroidDeviceInfo androidInfo = await deviceInfo.androidInfo;
deviceIdentifier = androidInfo.androidId;
} else if (Platform.isIOS) {
IosDeviceInfo iosInfo = await deviceInfo.iosInfo;
deviceIdentifier = iosInfo.identifierForVendor;
} else if (kIsWeb) {
// The web doesnt have a device UID, so use a combination fingerprint as an example
WebBrowserInfo webInfo = await deviceInfo.webBrowserInfo;
deviceIdentifier = webInfo.vendor + webInfo.userAgent + webInfo.hardwareConcurrency.toString();
} else if (Platform.isLinux) {
LinuxDeviceInfo linuxInfo = await deviceInfo.linuxInfo;
deviceIdentifier = linuxInfo.machineId;
}
return deviceIdentifier;
}

I release a new flutter plugin client_information might help. It provide a simple way to get some basic device information from your application user.

1. add to pubspec.yaml

  dependencies:
...
client_information: ^1.0.1

2. import to your project

import 'package:client_information/client_information.dart';

3. then you can get device ID like this

/// Support on iOS, Android and web project
Future<String> getDeviceId() async {
return (await ClientInformation.fetch()).deviceId;
}

Add the following code in your .yaml file.

device_info_plus: ^1.0.0

I used the following approach to get the device info that support in all platforms (i.e.) Android, IOS and Web.

import 'dart:io';
import 'package:device_info_plus/device_info_plus.dart';
import 'package:flutter/foundation.dart' show kIsWeb;


Future<String> getDeviceIdentifier() async {


String deviceIdentifier = "unknown";
DeviceInfoPlugin deviceInfo = DeviceInfoPlugin();


if (kIsWeb) {
WebBrowserInfo webInfo = await deviceInfo.webBrowserInfo;
deviceIdentifier = webInfo.vendor +
webInfo.userAgent +
webInfo.hardwareConcurrency.toString();
} else {
if (Platform.isAndroid) {
AndroidDeviceInfo androidInfo = await deviceInfo.androidInfo;
deviceIdentifier = androidInfo.androidId;
} else if (Platform.isIOS) {
IosDeviceInfo iosInfo = await deviceInfo.iosInfo;
deviceIdentifier = iosInfo.identifierForVendor;
} else if (Platform.isLinux) {
LinuxDeviceInfo linuxInfo = await deviceInfo.linuxInfo;
deviceIdentifier = linuxInfo.machineId;
}
}
return deviceIdentifier;
}

Latest:

The plugin device_info has given deprecation notice and replaced by device_info_plus

Example:

dependencies:
device_info_plus: ^2.1.0

How to use:

import 'package:device_info_plus/device_info_plus.dart';


DeviceInfoPlugin deviceInfo = DeviceInfoPlugin();


AndroidDeviceInfo androidInfo = await deviceInfo.androidInfo;
print('Running on ${androidInfo.model}');  // e.g. "Moto G (4)"


IosDeviceInfo iosInfo = await deviceInfo.iosInfo;
print('Running on ${iosInfo.utsname.machine}');  // e.g. "iPod7,1"


WebBrowserInfo webBrowserInfo = await deviceInfo.webBrowserInfo;
print('Running on ${webBrowserInfo.userAgent}');  // e.g. "Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:61.0) Gecko/20100101 Firefox/61.0"

You can check here full example:

For Unique ID:

You can use following code to get Unique ID:

if (kIsWeb) {
WebBrowserInfo webInfo = await deviceInfo.webBrowserInfo;
deviceIdentifier = webInfo.vendor +
webInfo.userAgent +
webInfo.hardwareConcurrency.toString();
} else {
if (Platform.isAndroid) {
AndroidDeviceInfo androidInfo = await deviceInfo.androidInfo;
deviceIdentifier = androidInfo.androidId;
} else if (Platform.isIOS) {
IosDeviceInfo iosInfo = await deviceInfo.iosInfo;
deviceIdentifier = iosInfo.identifierForVendor;
} else if (Platform.isLinux) {
LinuxDeviceInfo linuxInfo = await deviceInfo.linuxInfo;
deviceIdentifier = linuxInfo.machineId;
}
}

edit: There is no androidId on since v4.1.0.

Use device_info_plus package developed by Flutter community. This is how you can get IDs on both platform.

In your pubspec.yaml file add this:

dependencies:
device_info_plus: ^3.2.3

Create a method:

Future<String> getUniqueDeviceId() async {
String uniqueDeviceId = '';


var deviceInfo = DeviceInfoPlugin();


if (Platform.isIOS) { // import 'dart:io'
var iosDeviceInfo = await deviceInfo.iosInfo;
uniqueDeviceId = '${iosDeviceInfo.name}:${iosDeviceInfo.identifierForVendor}'; // unique ID on iOS
} else if(Platform.isAndroid) {
var androidDeviceInfo = await deviceInfo.androidInfo;
uniqueDeviceId = '${androidDeviceInfo.name}:${androidDeviceInfo.id}' ; // unique ID on Android
}
  

return uniqueDeviceId;


}

Usage:

String deviceId = await getUniqueDeviceId();

Output:

M2102J20SG::SKQ1.211006.001

Note:

1. Do not use androidDeviceInfo.androidId. This would change when your mac address changes. Mobile devices above Android OS 10/11 will generate a randomized MAC. This feature is enabled by default unless disabled manually. This would cause the androidId to change when switiching networks. You can confirm this by yourself by changing androidDeviceInfo.id to androidDeviceInfo.androidId above.

2. you can probably get away with using only androidDeviceInfo.name as it would not change ever.

3. androidDeviceInfo.id can also change if OS is updated as it is an android os version.

4. androidDeviceInfo.androidId should only be used if device uses fix mac address as mentioned in point 1. Otherwise, either use *.name only or androidDeviceInfo.id alongside with *.name.

androidID is removed since v4.1.0. Check the changelog.

android_id package is recommanded to get the correct androidId.

As of 2022, December, last status about getting device id :

device_info_plus don't give unique device id anymore. So I started to use platform_device_id package.

I tested it on Android and it worked as same as device_info previously and provide the same id value. It also has a simple usage :

   String deviceId = await PlatformDeviceId.getDeviceId;

This package uses updated android embedding version and also has null safety support.

android_id: ^0.1.3+1 Use this package but it only works on android.

device_info_plus: ^8.0.0 Use this package it works on IOS, Android, Web.