如何修复“在箭头函数结束时期望返回值”警告?

一切工作正常,但我有这个警告 Expected to return a value at the end of arrow function array-callback-return。我试着用 forEach代替 map,但是 <CommentItem />根本不显示。我该怎么补救?

  return this.props.comments.map((comment) => {
  

if (comment.hasComments === true) {
      

return (
<div key={comment.id}>
          

<CommentItem className="MainComment"/>


{this.props.comments.map(commentReply => {
              

if (commentReply.replyTo === comment.id) {
return (
<CommentItem className="SubComment"/>
) // return
} // if-statement
}) // map-function
} // map-function __begin
            

</div> // comment.id
          

) // return

201688 次浏览

The warning indicates that you're not returning something at the end of your map arrow function in every case.

A better approach to what you're trying to accomplish is first using a .filter and then a .map, like this:

this.props.comments
.filter(commentReply => commentReply.replyTo === comment.id)
.map((commentReply, idx) => <CommentItem key={idx} className="SubComment"/>);

The problem seems to be that you are not returning something in the event that your first if-case is false.

The error you are getting states that your arrow function (comment) => { doesn't have a return statement. While it does for when your if-case is true, it does not return anything for when it's false.

return this.props.comments.map((comment) => {
if (comment.hasComments === true) {
return (
<div key={comment.id}>
<CommentItem className="MainComment" />
{this.props.comments.map(commentReply => {
if (commentReply.replyTo === comment.id) {
return (
<CommentItem className="SubComment"/>
)
}
})
}
</div>
)
} else {
//return something here.
}
});

edit you should take a look at Kris' answer for how to better implement what you are trying to do.

A map() creates an array, so a return is expected for all code paths (if/elses).

If you don't want an array or to return data, use forEach instead.

The most upvoted answer, from Kris Selbekk, it is totally right. It is important to highlight though that it takes a functional approach, you will be looping through the this.props.comments array twice, the second time(looping) it will most probable skip a few elements that where filtered, but in case no comment was filtered you will loop through the whole array twice. If performance is not a concern in you project that is totally fine. In case performance is important a guard clause would be more appropriated as you would loop the array only once:

return this.props.comments.map((comment) => {
if (!comment.hasComments) return null;


return (
<div key={comment.id}>
<CommentItem className="MainComment"/>
{this.props.comments.map(commentReply => {
if (commentReply.replyTo !== comment.id) return null;


return <CommentItem className="SubComment"/>
})}
</div>
)
}

The main reason I'm pointing this out is because as a Junior Developer I did a lot of those mistakes(like looping the same array multiple times), so I thought i was worth mention it here.

PS: I would refactor your react component even more, as I'm not in favour of heavy logic in the html part of a JSX, but that is out of the topic of this question.

class Blog extends Component{
render(){
const posts1 = this.props.posts;
//console.log(posts)
const sidebar = (
<ul>
{posts1.map((post) => {
//Must use return to avoid this error.
return(
<li key={post.id}>
{post.title} - {post.content}
</li>
)
})
}
			

</ul>
);
const maincontent = this.props.posts.map((post) => {
return(
<div key={post.id}>
<h3>{post.title}</h3>
<p>{post.content}</p>
</div>
)
})
return(
<div>{sidebar}<hr/>{maincontent}</div>
);
}
}
const posts = [
{id: 1, title: 'Hello World', content: 'Welcome to learning React!'},
{id: 2, title: 'Installation', content: 'You can install React from npm.'}
];


ReactDOM.render(
<Blog posts={posts} />,
document.getElementById('root')
);

The easiest way only if you don't need return something it'ts just return null

You can use the for loop like so:

for(let i = 0 ; i < comments.length; i++){
if(comments[i].hasComments === true){
return (
<div key={comments[i].id}>
//content Here
</div> // comment.id
)
}
}