到 LocalDateTime 的长时间戳

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Try with Instant.ofEpochMilli() or Instant.ofEpochSecond() method with it-

long test_timestamp = 1499070300L;
LocalDateTime date =
LocalDateTime.ofInstant(Instant.ofEpochMilli(test_timestamp ), TimeZone
.getDefault().toZoneId());

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最佳答案

You need to pass timestamp in milliseconds:

long test_timestamp = 1499070300000L;
LocalDateTime triggerTime =
LocalDateTime.ofInstant(Instant.ofEpochMilli(test_timestamp),
TimeZone.getDefault().toZoneId());


System.out.println(triggerTime);

Result:

2017-07-03T10:25

Or use ofEpochSecond instead:

long test_timestamp = 1499070300L;
LocalDateTime triggerTime =
LocalDateTime.ofInstant(Instant.ofEpochSecond(test_timestamp),
TimeZone.getDefault().toZoneId());


System.out.println(triggerTime);

Result:

2017-07-03T10:25

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Try with the following..

long test_timestamp = 1499070300000L;
LocalDateTime triggerTime =
LocalDateTime.ofInstant(Instant.ofEpochMilli(test_timestamp), TimeZone
.getDefault().toZoneId());

By default 1499070300000 is int if it dosen't contain l in end.Also pass time in milliseconds.

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Your issue is that the timestamp is not in milliseconds but expressed in seconds from the Epoch date. Either multiply by 1000 your timestamp or use the Instant.ofEpochSecond().

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If you are using the Android threeten back port then the line you want is this

LocalDateTime.ofInstant(Instant.ofEpochMilli(startTime), ZoneId.systemDefault())

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SIMPLE and straight forward solution will (KOTLIN)

            val timeStamp:Long=559585985988
val sdf = SimpleDateFormat("hh:mm:ss a - MMM dd,yyyy", Locale.getDefault())
val tz = TimeZone.getDefault()
val now = Date()
val offsetFromUtc = tz.getOffset(now.time)
val localeTimeStr = sdf.format(timeStamp + offsetFromUtc) //add the offset to get the local time from the epoch timestamp