用 JavaScript 匹配精确的字符串

如何测试正则表达式是否匹配字符串 没错

var r = /a/;
r.test("a"); // returns true
r.test("ba"); // returns true
testExact(r, "ba"); // should return false
testExact(r, "a"); // should return true
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Either modify the pattern beforehand so that it only matches the entire string:

var r = /^a$/

or check afterward whether the pattern matched the whole string:

function matchExact(r, str) {
var match = str.match(r);
return match && str === match[0];
}

Write your regex differently:

var r = /^a$/;
r.test('a'); // true
r.test('ba'); // false

If you do not use any placeholders (as the "exactly" seems to imply), how about string comparison instead?

If you do use placeholders, ^ and $ match the beginning and the end of a string, respectively.

var data =   {"values": [
{"name":0,"value":0.12791263050161572},
{"name":1,"value":0.13158780927382124}
]};


//JSON to string conversion
var a = JSON.stringify(data);
// replace all name with "x"- global matching
var t = a.replace(/name/g,"x");
// replace exactly the value rather than all values
var d = t.replace(/"value"/g, '"y"');
// String to JSON conversion
var data = JSON.parse(d);

Here's what is (IMO) by far the best solution in one line, per modern javascript standards:

const str1 = 'abc';
const str2 = 'abc';
return (str1 === str2); // true




const str1 = 'abcd';
const str2 = 'abc';
return (str1 === str2); // false


const str1 = 'abc';
const str2 = 'abcd';
return (str1 === str2); // false

In case anyone receives an error like

Syntax Error: Invalid regular expression

by using the .match() function. You could always go back to the roots: !!note this code is for matchin an exact string, if you want to search for an exact phrase in a string, you should filter it before hand

console.log("Exact data found: ", hasExactString("?hello", "?hello"))


console.log("Exact data found: ", hasExactString("?hello", "?helloBye"))




function hasExactString(data, searchTerm) {
console.log("search for ", searchTerm, " in ", data);
data = data.toLowerCase(); //if search term should be case insensitive
const searchExpressionLength = searchTerm.length;
const dataInputLength = data.length;
if (dataInputLength != searchExpressionLength) {
return false;
}
else {
//search letter by letter -back to the roots
for (var i = 0; i < searchExpressionLength; i++) {
if (data[i] != searchTerm[i]) {
return false;
}
}
return true;
}
}

...13 years late, but nonetheless^^