在 Python 中获取没有扩展的文件名

如果我有这样的文件名:

1.1.1.1.1.jpg


1.1.jpg


1.jpg

如果没有扩展名，我怎么能只得到文件名? 正则表达式是否合适？

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最佳答案

In most cases, you shouldn't use a regex for that.

os.path.splitext(filename)[0]

This will also handle a filename like .bashrc correctly by keeping the whole name.

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>>> import os
>>> os.path.splitext("1.1.1.1.1.jpg")
('1.1.1.1.1', '.jpg')

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No need for regex. os.path.splitext is your friend:

os.path.splitext('1.1.1.jpg')
>>> ('1.1.1', '.jpg')

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If I had to do this with a regex, I'd do it like this:

s = re.sub(r'\.jpg$', '', s)

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You can use stem method to get file name.

Here is an example:

from pathlib import Path


p = Path(r"\\some_directory\subdirectory\my_file.txt")
print(p.stem)
# my_file

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One can also use the string slicing.

>>> "1.1.1.1.1.jpg"[:-len(".jpg")]
'1.1.1.1.1'