How to create python bytes object from long hex string?

I have a long sequence of hex digits in a string, such as

000000000000484240FA063DE5D0B744ADBED63A81FAEA390000C8428640A43D5005BD44

only much longer, several kilobytes. Is there a builtin way to convert this to a bytes object in python 2.6/3?

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小开

from binascii import unhexlify
b = unhexlify(myhexstr)

小开

你可以使用十六进制编解码器。例如:

>>> s='000000000000484240FA063DE5D0B744ADBED63A81FAEA390000C8428640A43D5005BD44'
>>> s.decode('hex')
'\x00\x00\x00\x00\x00\x00HB@\xfa\x06=\xe5\xd0\xb7D\xad\xbe\xd6:\x81\xfa\xea9\x00\x00\xc8B\x86@\xa4=P\x05\xbdD'

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最佳答案

result = bytes.fromhex(some_hex_string)

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工作于 Python 2.7及更高版本，包括 python3:

result = bytearray.fromhex('deadbeef')

Note: There seems to be a bug with the bytearray.fromhex() function in Python 2.6. The python.org documentation states that the function accepts a string as an argument, but when applied, the following error is thrown:

>>> bytearray.fromhex('B9 01EF')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: fromhex() argument 1 must be unicode, not str`

小开

import binascii


binascii.a2b_hex(hex_string)

我就是这么做的。