How to display a "busy" indicator with jQuery?

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yes, it's really just a matter of showing/hiding an animated gif.

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I did it in my project ,

make a div with back ground url as gif , which is nothing but animation gif

<div class="busyindicatorClass"> </div>


.busyindicatorClass
{
background-url///give animation here
}

in your ajax call , add this class to the div and in ajax success remove the class.

it will do the trick thatsit.

let me know if you need antthing else , i can give you more details

in the ajax success remove the class

success: function(data) {
remove class using jquery
}

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最佳答案

You can just show / hide a gif, but you can also embed that to ajaxSetup, so it's called on every ajax request.

$.ajaxSetup({
beforeSend:function(){
// show gif here, eg:
$("#loading").show();
},
complete:function(){
// hide gif here, eg:
$("#loading").hide();
}
});

One note is that if you want to do an specific ajax request without having the loading spinner, you can do it like this:

$.ajax({
global: false,
// stuff
});

That way the previous $.ajaxSetup we did will not affect the request with global: false.

More details available at: http://api.jquery.com/jQuery.ajaxSetup

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I tend to just show/hide a IMG as other have stated. I found a good website which generates "loading gifs"

Link I just put it inside a div and hide by default display: none; (css) then when you call the function show the image, once its complete hide it again.

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The jQuery documentation recommends doing something like the following:

$( document ).ajaxStart(function() {
$( "#loading" ).show();
}).ajaxStop(function() {
$( "#loading" ).hide();
});

Where #loading is the element with your busy indicator in it.

References:

http://api.jquery.com/ajaxStart/
http://api.jquery.com/ajaxStop/
In addition, jQuery.ajaxSetup API explicitly recommends avoiding jQuery.ajaxSetup for these:

Note: Global callback functions should be set with their respective global Ajax event handler methods—.ajaxStart(), .ajaxStop(), .ajaxComplete(), .ajaxError(), .ajaxSuccess(), .ajaxSend()—rather than within the options object for $.ajaxSetup().

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I did it in my project:

Global Events in application.js:

$(document).bind("ajaxSend", function(){
$("#loading").show();
}).bind("ajaxComplete", function(){
$("#loading").hide();
});

"loading" is the element to show and hide!

References: http://api.jquery.com/Ajax_Events/

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I had to use

HTML:
<img id="loading" src="~/Images/spinner.gif" alt="Updating ..." style="display: none;" />


In script file:
// invoked when sending ajax request
$(document).ajaxSend(function () {
$("#loading").show();
});


// invoked when sending ajax completed
$(document).ajaxComplete(function () {
$("#loading").hide();
});

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Old thread, but i wanted to update since i worked on this problem today, i didnt have jquery in my project so i did it the plain old javascript way, i also needed to block the content on the screen so in my xhtml

    <img id="loading" src="#{request.contextPath}/images/spinner.gif" style="display: none;"/>

in my javascript

    document.getElementsByClassName('myclass').style.opacity = '0.7'
document.getElementById('loading').style.display = "block";

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To extend Rodrigo's solution a little - for requests that are executed frequently, you may only want to display the loading image if the request takes more than a minimum time interval, otherwise the image will be continually popping up and quickly disappearing

var loading = false;


$.ajaxSetup({
beforeSend: function () {
// Display loading icon if AJAX call takes >1 second
loading = true;
setTimeout(function () {
if (loading) {
// show loading image
}
}, 1000);
},
complete: function () {
loading = false;
// hide loading image
}
});