设置 WebRequest 的主体数据

我在 ASP.NET 中创建了一个 web 请求，我需要向主体添加一些数据。我该怎么做？

var request = HttpWebRequest.Create(targetURL);
request.Method = "PUT";
response = (HttpWebResponse)request.GetResponse();
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看看我的另一个答案。

原创的

var request = (HttpWebRequest)WebRequest.Create("https://example.com/endpoint");


string stringData = ""; // place body here
var data = Encoding.Default.GetBytes(stringData); // note: choose appropriate encoding


request.Method = "PUT";
request.ContentType = ""; // place MIME type here
request.ContentLength = data.Length;


var newStream = request.GetRequestStream(); // get a ref to the request body so it can be modified
newStream.Write(data, 0, data.Length);
newStream.Close();
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最佳答案

用 HttpWebRequest.GetRequestStream

来自 http://msdn.microsoft.com/en-us/library/d4cek6cc.aspx的代码示例

string postData = "firstone=" + inputData;
ASCIIEncoding encoding = new ASCIIEncoding ();
byte[] byte1 = encoding.GetBytes (postData);


// Set the content type of the data being posted.
myHttpWebRequest.ContentType = "application/x-www-form-urlencoded";


// Set the content length of the string being posted.
myHttpWebRequest.ContentLength = byte1.Length;


Stream newStream = myHttpWebRequest.GetRequestStream ();


newStream.Write (byte1, 0, byte1.Length);

来自我自己的一个代码:

var request = (HttpWebRequest)WebRequest.Create(uri);
request.Credentials = this.credentials;
request.Method = method;
request.ContentType = "application/atom+xml;type=entry";
using (Stream requestStream = request.GetRequestStream())
using (var xmlWriter = XmlWriter.Create(requestStream, new XmlWriterSettings() { Indent = true, NewLineHandling = NewLineHandling.Entitize, }))
{
cmisAtomEntry.WriteXml(xmlWriter);
}


try
{
return (HttpWebResponse)request.GetResponse();
}
catch (WebException wex)
{
var httpResponse = wex.Response as HttpWebResponse;
if (httpResponse != null)
{
throw new ApplicationException(string.Format(
"Remote server call {0} {1} resulted in a http error {2} {3}.",
method,
uri,
httpResponse.StatusCode,
httpResponse.StatusDescription), wex);
}
else
{
throw new ApplicationException(string.Format(
"Remote server call {0} {1} resulted in an error.",
method,
uri), wex);
}
}
catch (Exception)
{
throw;
}
小开

这个话题的答案都很棒。不过我想再提一个。最有可能的情况是，您已经获得了一个 api，并希望将其放入您的 c # 项目中。 使用 Postman，您可以在那里设置和测试 api 调用，一旦它正常运行，您可以简单地单击“ Code”，您正在处理的请求将被写入 c # 代码片段。像这样:

var client = new RestClient("https://api.XXXXX.nl/oauth/token");
client.Timeout = -1;
var request = new RestRequest(Method.POST);
request.AddHeader("Authorization", "Basic   N2I1YTM4************************************jI0YzJhNDg=");
request.AddHeader("Content-Type", "application/x-www-form-urlencoded");
request.AddHeader("Content-Type", "application/x-www-form-urlencoded");
request.AddParameter("grant_type", "password");
request.AddParameter("username", "development+XXXXXXXX-admin@XXXXXXX.XXXX");
request.AddParameter("password", "XXXXXXXXXXXXX");
IRestResponse response = client.Execute(request);
Console.WriteLine(response.Content);

上面的代码依赖于可以轻松安装的 nuget 包 RestSharp。


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