JavaBigDecimal: 四舍五入到最接近的整数值

You can use setScale() to reduce the number of fractional digits to zero. Assuming value holds the value to be rounded:

BigDecimal scaled = value.setScale(0, RoundingMode.HALF_UP);
System.out.println(value + " -> " + scaled);

Using round() is a bit more involved as it requires you to specify the number of digits to be retained. In your examples this would be 3, but this is not valid for all values:

BigDecimal rounded = value.round(new MathContext(3, RoundingMode.HALF_UP));
System.out.println(value + " -> " + rounded);

(Note that BigDecimal objects are immutable; both setScale and round will return a new object.)

I don't think you can round it like that in a single command. Try

    ArrayList<BigDecimal> list = new ArrayList<BigDecimal>();
list.add(new BigDecimal("100.12"));
list.add(new BigDecimal("100.44"));
list.add(new BigDecimal("100.50"));
list.add(new BigDecimal("100.75"));


for (BigDecimal bd : list){
System.out.println(bd+" -> "+bd.setScale(0,RoundingMode.HALF_UP).setScale(2));
}


Output:
100.12 -> 100.00
100.44 -> 100.00
100.50 -> 101.00
100.75 -> 101.00

I tested for the rest of your examples and it returns the wanted values, but I don't guarantee its correctness.

Here's an awfully complicated solution, but it works:

public static BigDecimal roundBigDecimal(final BigDecimal input){
return input.round(
new MathContext(
input.toBigInteger().toString().length(),
RoundingMode.HALF_UP
)
);
}

Test Code:

List<BigDecimal> bigDecimals =
Arrays.asList(new BigDecimal("100.12"),
new BigDecimal("100.44"),
new BigDecimal("100.50"),
new BigDecimal("100.75"));
for(final BigDecimal bd : bigDecimals){
System.out.println(roundBigDecimal(bd).toPlainString());
}

Output:

100
100
101
101

You want

round(new MathContext(0));  // or perhaps another math context with rounding mode HALF_UP

Simply look at:

http://download.oracle.com/javase/6/docs/api/java/math/BigDecimal.html#ROUND_HALF_UP

and:

setScale(int precision, int roundingMode)

Or if using Java 6, then

http://download.oracle.com/javase/6/docs/api/java/math/RoundingMode.html#HALF_UP

http://download.oracle.com/javase/6/docs/api/java/math/MathContext.html

and either:

setScale(int precision, RoundingMode mode);
round(MathContext mc);

If i go by Grodriguez's answer

System.out.println("" + value);
value = value.setScale(0, BigDecimal.ROUND_HALF_UP);
System.out.println("" + value);

This is the output

100.23 -> 100
100.77 -> 101

Which isn't quite what i want, so i ended up doing this..

System.out.println("" + value);
value = value.setScale(0, BigDecimal.ROUND_HALF_UP);
value = value.setScale(2, BigDecimal.ROUND_HALF_UP);
System.out.println("" + value);

This is what i get

100.23 -> 100.00
100.77 -> 101.00

This solves my problem for now .. : ) Thank you all.

If neither .round() nor .setScale() seem intuitive to you, you can use this code to round to any integer steps of precision (e.g. round in 10s, 25s, 50s, 100s, ...).

Usage:

int distance = roundN(_distance, 5);

Declaration:

public static BigDecimal roundN(BigDecimal num, int precision){
BigDecimal remainder = num.remainder(BigDecimal.valueOf(precision));
System.out.println("remainder: " + remainder);


if (remainder.compareTo(BigDecimal.valueOf((precision / 2))) < 0 ){
System.out.println("round down");
return num.subtract(remainder);
} else {
BigDecimal neg = remainder.negate().add(BigDecimal.valueOf(precision));
System.out.println("round up");
return num.add(neg);
}
}

Trailing .00 can be appended to the result on demand.